Answer
Verified
397.2k+ views
Hint: We must have a basic idea of the combination of errors. We will firstly find g in terms of T. Then we will use the formula to find percentage error and by doing suitable calculations after substituting the given values in the formula, we will obtain our desired result.
Formula used:
\[\begin{align}
& z=\dfrac{{{A}^{p}}{{B}^{q}}}{{{C}^{r}}} \\
& \dfrac{\Delta Z}{Z}=p\dfrac{\Delta Z}{Z}+q\dfrac{\Delta Z}{Z}+r\dfrac{\Delta Z}{Z} \\
\end{align}\]
Complete step by step answer:
As given in the quention
\[T=2\pi \sqrt{\dfrac{L}{g}}\]
Firstly we will change the equation in terms of g.
We will square on both the sides .
\[\begin{align}
& {{T}^{2}}=4{{\pi }^{2}}\dfrac{L}{g} \\
& g=4{{\pi }^{2}}\dfrac{L}{{{T}^{2}}} \\
\end{align}\]
Now we will use the formula to find percentage error in g we know the formula is
\[\dfrac{\Delta Z}{Z}\times 100=p\dfrac{\Delta Z}{Z}\times 100+q\dfrac{\Delta Z}{Z}\times 100+r\dfrac{\Delta Z}{Z}\times 100\]
Now L=20.0 cm , \[\Delta \]L=1mm =0.1 cm ,T for 100 oscillations =90 s , \[\Delta \]T=1s.
\[\therefore \dfrac{\Delta g}{g}\times 100=\dfrac{\Delta L}{L}\times 100+2\times \dfrac{\Delta T}{T}\times 100\]
Now putting values we get
\[\begin{align}
& \therefore \dfrac{\Delta g}{g}\times 100=\dfrac{0.1}{20}\times 100+2\times \dfrac{1}{90}\times 100 \\
& =0.5+2.22=2.72\%=3\% \\
\end{align}\]
Accuracy in determination of g is 3%.
Hence, the correct option is (D).
Additional Information:
All measurements of physical quantities are uncertain and imprecise to some limit. There are three sources of errors. Negligence or inexperience of a person. Faulty apparatus. Inappropriate method or technique. Difference between error and uncertainties.
The basic difference between errors and uncertainties is that error is the difference between the calculated value and actual value, while uncertainty is usually described as an error in measurement.
Note:
We know in all mathematical operations errors are of additive nature. If a quantity appears with a powerless than one in an expression, then its error contribution in the final result is reduced. Calculations must be performed carefully. There are two different formulas for calculating errors and a percentage so one should be careful while using it.
Formula used:
\[\begin{align}
& z=\dfrac{{{A}^{p}}{{B}^{q}}}{{{C}^{r}}} \\
& \dfrac{\Delta Z}{Z}=p\dfrac{\Delta Z}{Z}+q\dfrac{\Delta Z}{Z}+r\dfrac{\Delta Z}{Z} \\
\end{align}\]
Complete step by step answer:
As given in the quention
\[T=2\pi \sqrt{\dfrac{L}{g}}\]
Firstly we will change the equation in terms of g.
We will square on both the sides .
\[\begin{align}
& {{T}^{2}}=4{{\pi }^{2}}\dfrac{L}{g} \\
& g=4{{\pi }^{2}}\dfrac{L}{{{T}^{2}}} \\
\end{align}\]
Now we will use the formula to find percentage error in g we know the formula is
\[\dfrac{\Delta Z}{Z}\times 100=p\dfrac{\Delta Z}{Z}\times 100+q\dfrac{\Delta Z}{Z}\times 100+r\dfrac{\Delta Z}{Z}\times 100\]
Now L=20.0 cm , \[\Delta \]L=1mm =0.1 cm ,T for 100 oscillations =90 s , \[\Delta \]T=1s.
\[\therefore \dfrac{\Delta g}{g}\times 100=\dfrac{\Delta L}{L}\times 100+2\times \dfrac{\Delta T}{T}\times 100\]
Now putting values we get
\[\begin{align}
& \therefore \dfrac{\Delta g}{g}\times 100=\dfrac{0.1}{20}\times 100+2\times \dfrac{1}{90}\times 100 \\
& =0.5+2.22=2.72\%=3\% \\
\end{align}\]
Accuracy in determination of g is 3%.
Hence, the correct option is (D).
Additional Information:
All measurements of physical quantities are uncertain and imprecise to some limit. There are three sources of errors. Negligence or inexperience of a person. Faulty apparatus. Inappropriate method or technique. Difference between error and uncertainties.
The basic difference between errors and uncertainties is that error is the difference between the calculated value and actual value, while uncertainty is usually described as an error in measurement.
Note:
We know in all mathematical operations errors are of additive nature. If a quantity appears with a powerless than one in an expression, then its error contribution in the final result is reduced. Calculations must be performed carefully. There are two different formulas for calculating errors and a percentage so one should be careful while using it.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The branch of science which deals with nature and natural class 10 physics CBSE
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Select the word that is correctly spelled a Twelveth class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE