
The term $\dfrac{{ - dx}}{{dt}}$ in the expression refers to:
A) The concentration of reactants
B) Increase in concentration of reactants
C) Decrease in concentration of reactants
D) The average rate of reaction
Answer
544.2k+ views
Hint: For any reaction in chemical kinetics we can write the expression of the rate, in that there is always a decrease in the concentration of reactants while an increase in concentration of products. This decrease of reactant concentration is because of the fact that reactants are changing into products that’s why their amount is decreasing and product amount is increasing.
Complete step-by-step answer:
Let’s understand the concept by taking an example of reaction, in this reaction we have A and B which are converting into product C. So the rate is the velocity by which the reaction is taking place. $A + B\xrightarrow{k}\,C$ Here, in this reaction (k) is the rate constant if the reaction takes place in the presence of a catalyst then the rate will be higher for faster reaction.
Now see if we want to write the rate expression we can include the concentration of A and B because these are the reactants. Also, we can write the rate as decrease in concentration of reactants.
$Rate = \,k\,\left[ A \right]\,\left[ B \right]$
$Rate = \,\dfrac{{ - d\left[ A \right]}}{{dt}}$ And also $Rate = \,\dfrac{{ - d\left[ B \right]}}{{dt}}$
So, here $\dfrac{{ - d\left[ A \right]}}{{dt}}$ and $\,\dfrac{{ - d\left[ B \right]}}{{dt}}$ gives the information as the decrease in the concentration of reactants. Similarly in the above question, we have given $\dfrac{{ - dx}}{{dt}}$ which will also give the decrease in the concentration of reactants.
Hence the correct answer is option ‘C’.
Note: When you are solving the equation rate the negative sign is put before the rate of reactants just to make their concentration position. There is a decrease in the concentration of reactant and increase in the concentration of products. The rate expression is written on behalf of reactants and products by putting stoichiometric coefficients.
Complete step-by-step answer:
Let’s understand the concept by taking an example of reaction, in this reaction we have A and B which are converting into product C. So the rate is the velocity by which the reaction is taking place. $A + B\xrightarrow{k}\,C$ Here, in this reaction (k) is the rate constant if the reaction takes place in the presence of a catalyst then the rate will be higher for faster reaction.
Now see if we want to write the rate expression we can include the concentration of A and B because these are the reactants. Also, we can write the rate as decrease in concentration of reactants.
$Rate = \,k\,\left[ A \right]\,\left[ B \right]$
$Rate = \,\dfrac{{ - d\left[ A \right]}}{{dt}}$ And also $Rate = \,\dfrac{{ - d\left[ B \right]}}{{dt}}$
So, here $\dfrac{{ - d\left[ A \right]}}{{dt}}$ and $\,\dfrac{{ - d\left[ B \right]}}{{dt}}$ gives the information as the decrease in the concentration of reactants. Similarly in the above question, we have given $\dfrac{{ - dx}}{{dt}}$ which will also give the decrease in the concentration of reactants.
Hence the correct answer is option ‘C’.
Note: When you are solving the equation rate the negative sign is put before the rate of reactants just to make their concentration position. There is a decrease in the concentration of reactant and increase in the concentration of products. The rate expression is written on behalf of reactants and products by putting stoichiometric coefficients.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

