
The temperature recorded in Ooty on a particular day is\[-{{4}^{\circ }}C\]. It decreased by \[-{{6}^{\circ }}C\]on the next day. What was the temperature recorded?
Answer
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Hint: In order to find the temperature recorded on that day, firstly convert both the temperatures to Kelvin scale, by using the formula\[K{{=}^{\circ }}C+273\], after that, find the next day’s temperature by subtracting \[-{{6}^{\circ }}C\]from the present day’s temperature.
Formula used: The formula used here is to convert the temperature from \[^{\circ }C\] to \[K\], which says that the temperature in kelvin equals the temperature in Celsius plus \[273\]
i.e., \[K{{=}^{\circ }}C+273\]
In order to find the temperature, after the decrease,
Temperature after equals the temperature before plus the difference in negative.
\[T2=T1+\left( -Diff \right)\]
Complete step-by-step solution:
Firstly, in order to find the temperature on the next day, let us convert the present day’ temperature to kelvin scale from degree Celsius one.
Given that the temperature of OOTY on a particular day is \[-{{4}^{\circ }}C\]
In Kelvin form,
\[\begin{align}
& T1=\left( -{{4}^{\circ }}C+273 \right)K \\
& \Rightarrow T1=269K \\
\end{align}\]
As it I given that the next day the temperature falls by \[-{{6}^{\circ }}C\]
Now, the temperature difference in degree Celsius is equal to that in kelvin
So the temp difference is \[-6K\]
Therefore, the temperature the next day is
\[\Rightarrow T2=269K-6K=263K\]
So, in \[^{\circ }C\] , temperature the next day is
\[\begin{align}
& T2={{\left( 263-273 \right)}^{\circ }}C \\
& \Rightarrow T2=-{{10}^{\circ }}C \\
\end{align}\]
Note: Alternatively, the question can also be solved directly without converting it to the kelvin scale in the way:
\[\begin{align}
& T2=T1+\left( -Diff \right) \\
& \Rightarrow T2=-4+\left( -6 \right)=-{{10}^{\circ }}C \\
\end{align}\]
If the temperature difference were given in positive, then the difference had been simply subtracted from the temperature on the day before to get the temperature after the decrease on the next day
Formula used: The formula used here is to convert the temperature from \[^{\circ }C\] to \[K\], which says that the temperature in kelvin equals the temperature in Celsius plus \[273\]
i.e., \[K{{=}^{\circ }}C+273\]
In order to find the temperature, after the decrease,
Temperature after equals the temperature before plus the difference in negative.
\[T2=T1+\left( -Diff \right)\]
Complete step-by-step solution:
Firstly, in order to find the temperature on the next day, let us convert the present day’ temperature to kelvin scale from degree Celsius one.
Given that the temperature of OOTY on a particular day is \[-{{4}^{\circ }}C\]
In Kelvin form,
\[\begin{align}
& T1=\left( -{{4}^{\circ }}C+273 \right)K \\
& \Rightarrow T1=269K \\
\end{align}\]
As it I given that the next day the temperature falls by \[-{{6}^{\circ }}C\]
Now, the temperature difference in degree Celsius is equal to that in kelvin
So the temp difference is \[-6K\]
Therefore, the temperature the next day is
\[\Rightarrow T2=269K-6K=263K\]
So, in \[^{\circ }C\] , temperature the next day is
\[\begin{align}
& T2={{\left( 263-273 \right)}^{\circ }}C \\
& \Rightarrow T2=-{{10}^{\circ }}C \\
\end{align}\]
Note: Alternatively, the question can also be solved directly without converting it to the kelvin scale in the way:
\[\begin{align}
& T2=T1+\left( -Diff \right) \\
& \Rightarrow T2=-4+\left( -6 \right)=-{{10}^{\circ }}C \\
\end{align}\]
If the temperature difference were given in positive, then the difference had been simply subtracted from the temperature on the day before to get the temperature after the decrease on the next day
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