Question

The temperature of a place at $12:00$ noon was $ + 5^\circ C$. The temperature increased by $3^\circ C$ in the first hour and decreased by $1^\circ C$ in the next second hour. What was the temperature at $2:00p.m.$?

Answer 1

Hint: Here it is given that the temperature at $12:00$ noon was $ + 5^\circ C$ and then the temperature increased by $3^\circ C$ in the first hour and decreased by $1^\circ C$ in the next second hour and we have to calculate the temperature at $2:00p.m.$ so we will use addition and subtraction to get the required result for this question.

Complete answer:
According to the question the temperature at $12:00$ noon was $ + 5^\circ C$ and then the temperature increased by $3^\circ C$ in the first hour.
We can say that the temperature in the next hour i.e., at $1:00p.m.$ is the sum of the temperature at $12:00$ and the increase in the temperature in the next hour.
So, the temperature at $1:00p.m.$ is $5 + 3 = 8^\circ C$
Now it is given that the temperature is decreased by $1^\circ C$ in the next second hour.
So, the temperature at $2:00p.m.$ will be the difference of temperature at $1:00p.m.$ and the decrease in the temperature in the next second hour.
Therefore, the temperature at $2:00p.m.$ is $8 - 1 = 7^\circ C$
Hence, the temperature at $2:00p.m.$ will be $7^\circ C$.

Note:
In order for solving these types of problems one must aware with the concepts of clock and time that after what time what time will come if we don’t know then we cannot solve these types of questions and we must aware with the concepts of a.m. and p.m. as the time will change if these are given.