
The table shows the number of boys and girls that wear spectacles in class 5.
Class Number of boys Number of girls 5-A 16 12 5-B 12 6 5-C 8 5 5-D 19 2
What is the fraction of girls in class 5-C to the number of boys in 5A and 5-B?
\[\begin{align}
& A.\dfrac{5}{12} \\
& B.\dfrac{5}{16} \\
& C.\dfrac{5}{28} \\
& D.\dfrac{5}{38} \\
\end{align}\]
| Class | Number of boys | Number of girls |
| 5-A | 16 | 12 |
| 5-B | 12 | 6 |
| 5-C | 8 | 5 |
| 5-D | 19 | 2 |
Answer
578.1k+ views
Hint: In this question, we are given a number of boys and a number of girl’s four sections of class 5 who wear spectacles. We have to find fraction of girls in class 5-C to the number of boys in 5-A and 5-B. For this, we will first note the number of girls in 5-C and then find number of boys in 5-A and 5-B. After this, we will find required fraction by putting number of girls in 5-C in numerator and number of boys in 5-A and 5-B in denominator.
Complete step-by-step answer:
We are given that there are 16 boys and 12 girls in class 5-A who wear spectacles. Also there are 12 boys and 6 girls in class 5-B, 8 boys and 5 girls in class 5-C and 19 boys and 2 girls in class 5-D to wear spectacles. Using this data, we have to find the fraction of girls in class 5- C to the number of boys in 5-A and 5-B.
For this, let us first find the number of girls in class 5-C who wear spectacles. As we can observe from the table, there are 5 girls in class 5-C who wear spectacles.
Now let us find the number of boys in class 5-A and 5-B. As we can see from the table, there are 16 boys in 5-A who wear spectacles and 12 boys in class 5-B who wear spectacles. So there are a total 16+12 = 28 boys in class 5-A and 5-B who wear spectacles.
Now to find required fraction, we will put number of girls in 5-C who wear spectacle that is 5 in numerator and number of boys in 5-A and 5-B who wear spectacle that is 28 in denominator we get:
\[\text{Fraction}=\dfrac{5}{28}\]
Hence, our required fraction is equal to $\dfrac{5}{28}$.
So, the correct answer is “Option C”.
Note: Students should know which value has to be put in the numerator and which value has to be put in the denominator. If the fraction can be reduced further, try to reduce it to get a simplified answer. Students should copy values from the table carefully so that there is no mistake while noting the value.
Complete step-by-step answer:
We are given that there are 16 boys and 12 girls in class 5-A who wear spectacles. Also there are 12 boys and 6 girls in class 5-B, 8 boys and 5 girls in class 5-C and 19 boys and 2 girls in class 5-D to wear spectacles. Using this data, we have to find the fraction of girls in class 5- C to the number of boys in 5-A and 5-B.
For this, let us first find the number of girls in class 5-C who wear spectacles. As we can observe from the table, there are 5 girls in class 5-C who wear spectacles.
Now let us find the number of boys in class 5-A and 5-B. As we can see from the table, there are 16 boys in 5-A who wear spectacles and 12 boys in class 5-B who wear spectacles. So there are a total 16+12 = 28 boys in class 5-A and 5-B who wear spectacles.
Now to find required fraction, we will put number of girls in 5-C who wear spectacle that is 5 in numerator and number of boys in 5-A and 5-B who wear spectacle that is 28 in denominator we get:
\[\text{Fraction}=\dfrac{5}{28}\]
Hence, our required fraction is equal to $\dfrac{5}{28}$.
So, the correct answer is “Option C”.
Note: Students should know which value has to be put in the numerator and which value has to be put in the denominator. If the fraction can be reduced further, try to reduce it to get a simplified answer. Students should copy values from the table carefully so that there is no mistake while noting the value.
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