
The surface area of a cube is $ 1536c{m^2} $ .
Find:
(i) The length of its edge.
(ii) Its volume
(iii) The volume of its material whose thickness is $ 5mm. $
Answer
568.2k+ views
Hint: Use the formulae of surface area and volume of a cube. Also remember that the sides of a cube are equal. Using the following properties find the given parameters asked.
Complete step-by-step answer:
Let $ a $ be the side of the cube.
$ S $ be the surface area of the cube.
$ V $ be the volume of the cube.
$ {V_m} $ be the volume of the material.
(i) We know that, surface area of a cube is the sum of the area of all the surfaces of the cube.
And every surface of a cube is square
$ \therefore S = 6{a^2} $
It is given that,
$ S = 1536c{m^2} $
$ \therefore 6{a^2} = 1536c{m^2} $
Dividing both the sides by $ 6 $ , we get
$ {a^2} = 256 $
Taking square root to both the sides, we get
$ a = +16 $
Area cannot be $ - ve. $
$ \therefore a = 16cm $
$ \therefore $ length of its edge is $ 16cm. $
(ii) Now, volume of the cube is given by
$ V = {a^3} $
$ \Rightarrow V = {16^3} $ $ (\because a = 16) $
$ \Rightarrow V = 4096c{m^3} $
Therefore, the volume of the cube is $ 4096c{m^3}. $
(iii) There is a material of thickness $ 5mm $ in the cube.
Let $ V' $ be the volume of the cube without material.
Then side of $ V' $ will be $ (a - 10mm) $ i.e. $ (a - 1)cm $
To get the length of the inner cube, we need to subtract $ 2 $ times the thickness from the original length. As the thickness of $ 5mm $ is to both the sides of the edge of the cube.
Therefore, volume of the cube inside the material is
$ V' = {(a - 1)^3} $
$ V' = {15^3} $ $ (\because a = 16) $
$ V' = 3375c{m^3} $
Therefore, the volume of the material will be $ {V_m} = V - V' $
$ \Rightarrow {V_m} = 4096 - 3375 $
$ \Rightarrow {V_m} = 721c{m^3} $
Therefore, the volume of the material is $ 721c{m^3} $
Note: Sub question (iii) is tricky. You should understand that the material is not added to the given cube. But the cube is made by the material off thickness of $ 5mm. $ That means we need to subtract $ 1cm $ from the side of the cube. Do not add it.
Complete step-by-step answer:
Let $ a $ be the side of the cube.
$ S $ be the surface area of the cube.
$ V $ be the volume of the cube.
$ {V_m} $ be the volume of the material.
(i) We know that, surface area of a cube is the sum of the area of all the surfaces of the cube.
And every surface of a cube is square
$ \therefore S = 6{a^2} $
It is given that,
$ S = 1536c{m^2} $
$ \therefore 6{a^2} = 1536c{m^2} $
Dividing both the sides by $ 6 $ , we get
$ {a^2} = 256 $
Taking square root to both the sides, we get
$ a = +16 $
Area cannot be $ - ve. $
$ \therefore a = 16cm $
$ \therefore $ length of its edge is $ 16cm. $
(ii) Now, volume of the cube is given by
$ V = {a^3} $
$ \Rightarrow V = {16^3} $ $ (\because a = 16) $
$ \Rightarrow V = 4096c{m^3} $
Therefore, the volume of the cube is $ 4096c{m^3}. $
(iii) There is a material of thickness $ 5mm $ in the cube.
Let $ V' $ be the volume of the cube without material.
Then side of $ V' $ will be $ (a - 10mm) $ i.e. $ (a - 1)cm $
To get the length of the inner cube, we need to subtract $ 2 $ times the thickness from the original length. As the thickness of $ 5mm $ is to both the sides of the edge of the cube.
Therefore, volume of the cube inside the material is
$ V' = {(a - 1)^3} $
$ V' = {15^3} $ $ (\because a = 16) $
$ V' = 3375c{m^3} $
Therefore, the volume of the material will be $ {V_m} = V - V' $
$ \Rightarrow {V_m} = 4096 - 3375 $
$ \Rightarrow {V_m} = 721c{m^3} $
Therefore, the volume of the material is $ 721c{m^3} $
Note: Sub question (iii) is tricky. You should understand that the material is not added to the given cube. But the cube is made by the material off thickness of $ 5mm. $ That means we need to subtract $ 1cm $ from the side of the cube. Do not add it.
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