The sum of two numbers is 405 and the ratio between the numbers is 8:7. Find the numbers.
Answer
545.7k+ views
Hint: We first assume the ratio constant and find the algebraic form of the numbers. We take the addition and equate with 405. We find the value of $x$ and then the numbers.
Complete step by step answer:
The sum of two numbers is 405 and the ratio between the numbers is 8:7.
We are taking $x$ as the ratio constant. Therefore, the numbers become $8x$ and $7x$.
We take the sum of the numbers in algebraic form which is $8x+7x=15x$.
Therefore, equating with 405 we get $15x=405\Rightarrow x=\dfrac{405}{15}$.
For any fraction $\dfrac{p}{q}$, we first find the G.C.D of the denominator and the numerator. If it’s 1 then it’s already in its simplified form and if the G.C.D of the denominator and the numerator is any other number d then we need to divide the denominator and the numerator with d and get the simplified fraction form as $\dfrac{{}^{p}/{}_{d}}{{}^{q}/{}_{d}}$.
For our given fraction $\dfrac{405}{15}$, the G.C.D of the denominator and the numerator is 15.
$\begin{align}
& 3\left| \!{\underline {\,
15,405 \,}} \right. \\
& 5\left| \!{\underline {\,
5,135 \,}} \right. \\
& 1\left| \!{\underline {\,
1,27 \,}} \right. \\
\end{align}$
The GCD is $3\times 5=15$.
Now we divide both the denominator and the numerator with 15 and get $\dfrac{{}^{405}/{}_{15}}{{}^{15}/{}_{15}}=27$.
The numbers are $8\times 27=216$ and $7\times 27=189$.
Note: We can also solve using unit form instead of $x$. If they are the number 8 and 7 then addition would have been 15. We find the numbers in that order where 15 represents 405. The ration increase gives the numbers.
Complete step by step answer:
The sum of two numbers is 405 and the ratio between the numbers is 8:7.
We are taking $x$ as the ratio constant. Therefore, the numbers become $8x$ and $7x$.
We take the sum of the numbers in algebraic form which is $8x+7x=15x$.
Therefore, equating with 405 we get $15x=405\Rightarrow x=\dfrac{405}{15}$.
For any fraction $\dfrac{p}{q}$, we first find the G.C.D of the denominator and the numerator. If it’s 1 then it’s already in its simplified form and if the G.C.D of the denominator and the numerator is any other number d then we need to divide the denominator and the numerator with d and get the simplified fraction form as $\dfrac{{}^{p}/{}_{d}}{{}^{q}/{}_{d}}$.
For our given fraction $\dfrac{405}{15}$, the G.C.D of the denominator and the numerator is 15.
$\begin{align}
& 3\left| \!{\underline {\,
15,405 \,}} \right. \\
& 5\left| \!{\underline {\,
5,135 \,}} \right. \\
& 1\left| \!{\underline {\,
1,27 \,}} \right. \\
\end{align}$
The GCD is $3\times 5=15$.
Now we divide both the denominator and the numerator with 15 and get $\dfrac{{}^{405}/{}_{15}}{{}^{15}/{}_{15}}=27$.
The numbers are $8\times 27=216$ and $7\times 27=189$.
Note: We can also solve using unit form instead of $x$. If they are the number 8 and 7 then addition would have been 15. We find the numbers in that order where 15 represents 405. The ration increase gives the numbers.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
What are the 12 elements of nature class 8 chemistry CBSE

Advantages and disadvantages of science

10 slogans on organ donation class 8 english CBSE

Summary of the poem Where the Mind is Without Fear class 8 english CBSE

What are the methods of reducing friction. Explain

Describe the elements of Belgian model for accommodating class 8 social science CBSE


