Question

The sum of first 50 natural numbers is:-
(a) 1275
(b) 51
(c) 1175
(d) None of these

Answer 1

Hint: Now, to solve this question, the formula that we are going to use is \[\left( \dfrac{n(n+1)}{2} \right)\].
Here, ‘n’ denotes the number of natural numbers up to which the sum is to be found.
So, in this question, ‘n’ = 50.

Complete step-by-step answer:
Before solving this question, we must know about Natural Numbers.
NATURAL NUMBERS- The natural numbers are those numbers that are used for counting and ordering anything. Whenever we count objects, we start from 1. So, natural numbers start from 1 and are till infinity.
For example: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11…..100, 156……….till infinite

Now, what we need to find is the sum of the first 50 natural numbers that are mentioned below.
The first 50 natural numbers are 1 to 50. That are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17 , 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50.
Let us find the sum of these numbers now:-
We will be using the same formula to find the sum of the first fifty natural numbers.
\[=\left( \dfrac{n(n+1)}{2} \right)\]
\[=\left( \dfrac{50(50+1)}{2} \right)\]
\[=\left( \dfrac{50(51)}{2} \right)\]
\[=\dfrac{2550}{2}\]
=1275
Therefore, the sum of the first fifty natural numbers is 1275.
Hence, option (a) is correct

So, the correct answer is “Option (a)”.

Note: Always remember that whole numbers are a set of numbers including the set of natural numbers (1 to infinity) and the integer '0'. Also remember that the sum of natural numbers will always be even so if you get an answer in decimal then again check your answer. Try not to make any calculation mistakes as this will change the final answer.