Question

The structure of $ 3 - $ Bromoprop $ - 1 - $ ene is:
(A) $ C{H_3} - C(Br) = C{H_2} $
(B) $ C{H_3} - CH = CH - Br $
(C) $ C{H_3} - C(Br) = CH - Br $
(D) $ Br - C{H_2} - CH = C{H_2} $

Answer 1

Hint :As we know that the allyl bromide is an organic halide. It is an alkylating agent used in synthesis of polymers and other organic compounds. Physically, allyl bromide is a colourless liquid with an intense, acrid and persistent smell. We know that the preferred IUPAC name is $ 3 - $ Bromoprop $ - 1 - $ ene.

Complete Step By Step Answer:
We know that the parent hydrocarbon is prop $ - 1 - $ ene. It contains $ 3 $ carbon atoms and one double bond. $ Br $ is substituent present at the third carbon atom.
In this compound, according to the $ IUPAC $ rule, the double bond is given preference over the bromo group. We can write the structure of $ 3 - $ Bromoprop $ - 1 - $ ene as $ Br - C{H_2} - CH = C{H_2} $ .
Hence the correct option is (D) $ Br - C{H_2} - CH = C{H_2} $ .

Note :
Before solving this kind of question we should be fully aware of their categories and their IUPAC names. IUPAC naming is a method to name chemical compounds as recommended by the International Union of Pure and Applied Chemistry.