Question

The strength (in $g/L$ ) of $10$ volume of ${H_2}{O_2}$ solution is:
A.)$10$
B.)$68$
C.)$60,70$
D.)$30,36$

Answer 1

Hint:The strength of the solution is determined by taking a note of the amount of solute present in the container in which solute and solution are present currently. The other definition can be; the concentration of solution in grams per liter.

Complete step by step answer:
-The mass of solute in grams dissolved in one litre of solution is called the strength of the solution.
The S.I. unit of strength is denoted by $g/ltr$.
-We know that,
Strength $ = $ Mass of solute present in total volume of the solution.
$10$ Volume of ${H_2}{O_2}$ means $1ltr$ of ${H_2}{O_2}$ will give $10ltr$ of oxygen at STP[standard temperature and pressure].
-The equation used is as follows:
$2{H_2}{O_2} \to 2{H_2}O + {O_2}$
-Mass of solute (${H_2}{O_2}$) present here $ = 68g$
-${O_2}$ will give $22.4ltr$ at STP.
-Since $22.4ltr$ of ${O_2}$ is obtained from $68g$ of ${H_2}{O_2}$.
-Thus, $10ltr$ of ${O_2}$is obtained from:
\[\dfrac{{68}}{{22.4}} \times 10 = 30.36gm/ltr\] [By using unitary method.]
-So the calculated strength of ${H_2}{O_2}$ is $30.36gm/ltr$ .
Hence option-D is our correct answer.

Note:
Molecular mass of ${H_2}{O_2}$ is $34.01g/mol$ , but since here in the equation $2$ ${H_2}{O_2}$ is written so we have to multiply the given molecular weight by $2$ which ultimately gives us $68g$.