
The standard potentials for and half reaction are \[ - 0.136V\] and \[ - 0.440V\] respectively. At what relative concentration of \[S{n^{2 + }}\] and \[F{e^{3 + }}\] will these have the same reduction potential?
Answer
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Hint: Standard potential : they are the physical quantities that represent essential properties of the system that evolve metals and gases on one hand and ions in the solution on the other. \[{E^o} = \] \[{E^o}\] of cathode-\[{E^o}\]of cathode Further,this can be used in the nernst equation:
Which states that \[{E^o} = \dfrac{{2.303RT}}{{nF}}\log {K_C}\].
Complete step-by-step answer: Standard potential : they are the physical quantities that represent essential properties of the system that evolve metals and gases on one hand and ions in the solution on the other.
Reduction potential:reduction potential is the measure of the tendency of a chemical species to acquire or lose electrons and form reduction and oxidation potential respectively.
Then we should apply the following formulas:
\[{E^o} = \] \[{E^o}\] of cathode-\[{E^o}\]of cathode
Further,this can be used in the nernst equation:
Which states that \[{E^o} = \dfrac{{2.303RT}}{{nF}}\log {K_C}\]
Where the value of \[{K_C}\] determines the extent of the cell reaction. This reaction takes place at equilibrium or when the reaction is about to attain equilibrium.
Note: Thus we can say that the above equation gives a relationship between equilibrium constant of the reaction and the standard potential of the cell in which that reaction takes place. Thus, equilibrium constant of the reaction is difficult to measure.
Which states that \[{E^o} = \dfrac{{2.303RT}}{{nF}}\log {K_C}\].
Complete step-by-step answer: Standard potential : they are the physical quantities that represent essential properties of the system that evolve metals and gases on one hand and ions in the solution on the other.
Reduction potential:reduction potential is the measure of the tendency of a chemical species to acquire or lose electrons and form reduction and oxidation potential respectively.
Then we should apply the following formulas:
\[{E^o} = \] \[{E^o}\] of cathode-\[{E^o}\]of cathode
Further,this can be used in the nernst equation:
Which states that \[{E^o} = \dfrac{{2.303RT}}{{nF}}\log {K_C}\]
Where the value of \[{K_C}\] determines the extent of the cell reaction. This reaction takes place at equilibrium or when the reaction is about to attain equilibrium.
Note: Thus we can say that the above equation gives a relationship between equilibrium constant of the reaction and the standard potential of the cell in which that reaction takes place. Thus, equilibrium constant of the reaction is difficult to measure.
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