
The square root of 2.9 up to two decimal places is:
A) 1.68
B) 1.70
C) 1.67
D) 1.71
Answer
573k+ views
Hint:We solve for the square root of the given number using the division method. Write the digits after the decimal in pair of two each starting from the right side and keep making pairs till all the digits are covered in the number ( digits before the decimal too). Then finding the suitable multiple of the term we divide the given number.
Complete step-by-step answer:
We expand the decimal number by writing three zeros after the number in decimal place.
The number \[2.9\]becomes \[2.9000\]
First we pair the digits in the number after the decimal point in pair of two each starting from the right side. Similarly we pair the digits before the decimal place.
\[2.9000 = \overline 2 .\overline {90} \overline {00} \]
Then we take the highest number whose square will be less than or equal to the first pair i.e. \[2\]
So, we know, \[1 \times 1 = 1,2 \times 2 = 4\]
We choose \[1 \times 1 = 1\] because \[1 < 2\]
Now we divide the number by taking this number as a divisor and taking the same number as quotient.
\[
1\mathop{\left){\vphantom{1{\overline 2 .\overline {90} \overline {00} }}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{{\overline 2 .\overline {90} \overline {00} }}}}
\limits^{\displaystyle \,\,\, 1} \\
- 1 \\
\overline { = 19000} \\
\]
Now the remainder becomes the next dividend and the new divisor is twice the old divisor followed by a digit which makes a number such that the square of that number will be less than or equal to the new dividend. We place the decimal in the quotient and then write the next digit in the quotient.
So, we have a new dividend as \[19000\] and we can have a divisor as \[2 \times 1\underline {} = 2\underline {} \]where blank is filled by the same digit.
Now we try to find a number in the lane of twenties whose square is less than or equal to our new dividend.
\[
21 \times 1 = 21 \\
22 \times 2 = 44 \\
23 \times 3 = 69 \\
24 \times 4 = 96 \\
25 \times 5 = 125 \\
26 \times 6 = 156 \\
27 \times 7 = 189 \\
28 \times 8 = 224 \]
We can clearly see that \[27 \times 7 = 189\] suits our requirement because \[189 < 190\]
Now we divide the dividend by the number \[27\] and the quotient \[7\] comes after the decimal beside the earlier quotient.
\[
27\mathop{\left){\vphantom{1{19000}}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{{19000}}}}
\limits^{\displaystyle \,\,\, {1.7}} \\
- 18900 \\
\overline { = 100} \\
\]
So, we have a new dividend as \[100\] and we can have a divisor as \[2 \times 27\underline {} = 34\underline {} \] where blank is filled by the same digit.
Now we try to find a number in the lane of three hundred and forties whose square is less than or equal to our new dividend.
\[
340 \times 0 = 0 \\
341 \times 1 = 341\]
We can clearly see that \[340 \times 0 = 0\] suits our requirement because \[0 < 100\]
Now we divide the dividend by the number \[340\] and the quotient \[0\] comes beside the earlier quotient.
\[
340\mathop{\left){\vphantom{1{100}}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{{100}}}}
\limits^{\displaystyle \,\,\, {1.70}} \\
- 00 \\
\overline { = 100}\]
So, we have quotient up to two decimal places.
Therefore, the square root of 2.9 is 1.70 up to two decimal places.
So, the correct answer is “Option B”.
Note:Students might make mistakes in finding the root up to two decimal places as they might not know that we can fix any number of zeros after the decimal and that will not change the value of the number. Also, when writing the division we need not write decimal in new dividends as it will just cause confusion.
Complete step-by-step answer:
We expand the decimal number by writing three zeros after the number in decimal place.
The number \[2.9\]becomes \[2.9000\]
First we pair the digits in the number after the decimal point in pair of two each starting from the right side. Similarly we pair the digits before the decimal place.
\[2.9000 = \overline 2 .\overline {90} \overline {00} \]
Then we take the highest number whose square will be less than or equal to the first pair i.e. \[2\]
So, we know, \[1 \times 1 = 1,2 \times 2 = 4\]
We choose \[1 \times 1 = 1\] because \[1 < 2\]
Now we divide the number by taking this number as a divisor and taking the same number as quotient.
\[
1\mathop{\left){\vphantom{1{\overline 2 .\overline {90} \overline {00} }}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{{\overline 2 .\overline {90} \overline {00} }}}}
\limits^{\displaystyle \,\,\, 1} \\
- 1 \\
\overline { = 19000} \\
\]
Now the remainder becomes the next dividend and the new divisor is twice the old divisor followed by a digit which makes a number such that the square of that number will be less than or equal to the new dividend. We place the decimal in the quotient and then write the next digit in the quotient.
So, we have a new dividend as \[19000\] and we can have a divisor as \[2 \times 1\underline {} = 2\underline {} \]where blank is filled by the same digit.
Now we try to find a number in the lane of twenties whose square is less than or equal to our new dividend.
\[
21 \times 1 = 21 \\
22 \times 2 = 44 \\
23 \times 3 = 69 \\
24 \times 4 = 96 \\
25 \times 5 = 125 \\
26 \times 6 = 156 \\
27 \times 7 = 189 \\
28 \times 8 = 224 \]
We can clearly see that \[27 \times 7 = 189\] suits our requirement because \[189 < 190\]
Now we divide the dividend by the number \[27\] and the quotient \[7\] comes after the decimal beside the earlier quotient.
\[
27\mathop{\left){\vphantom{1{19000}}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{{19000}}}}
\limits^{\displaystyle \,\,\, {1.7}} \\
- 18900 \\
\overline { = 100} \\
\]
So, we have a new dividend as \[100\] and we can have a divisor as \[2 \times 27\underline {} = 34\underline {} \] where blank is filled by the same digit.
Now we try to find a number in the lane of three hundred and forties whose square is less than or equal to our new dividend.
\[
340 \times 0 = 0 \\
341 \times 1 = 341\]
We can clearly see that \[340 \times 0 = 0\] suits our requirement because \[0 < 100\]
Now we divide the dividend by the number \[340\] and the quotient \[0\] comes beside the earlier quotient.
\[
340\mathop{\left){\vphantom{1{100}}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{{100}}}}
\limits^{\displaystyle \,\,\, {1.70}} \\
- 00 \\
\overline { = 100}\]
So, we have quotient up to two decimal places.
Therefore, the square root of 2.9 is 1.70 up to two decimal places.
So, the correct answer is “Option B”.
Note:Students might make mistakes in finding the root up to two decimal places as they might not know that we can fix any number of zeros after the decimal and that will not change the value of the number. Also, when writing the division we need not write decimal in new dividends as it will just cause confusion.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

