
The specific conductance of a salt of 0.01 M concentration is $1.061\times {{10}^{-4}}$. Molar conductance of the same solution will be_________.
A.\[1.061\times {{10}^{-4}}\]
B.1.061
C.10.61
D.106.1
Answer
588.9k+ views
Hint: We know that specific conductance of an electrolyte solution is a measure of its ability to conduct electricity. And molar conductivity is the conducting power of all the ions produced by dissolving one mole of an electrolyte in solution.
Step by step solution:
We know that, the molar conductance is denoted by lambda (${{\Lambda }_{m}}$) and its unit is $Sc{{m}^{2}}mo{{l}^{-1}}$. Specific conductance is represented by kappa ($\kappa $) and its unit is S/m. Here S is Siemens. And the formulas of molar conductance and specific conductance are:
Specific conductance ($\kappa $) = cell constant / resistance
Molar conductance (${{\Lambda }_{m}}$) = specific conductance x 1000 / C
= \[\dfrac{\kappa \times 1000}{C}\]
Where, C is the molarity
Given,
Molarity = 0.01 M,
Specific conductance = $1.061\times {{10}^{-4}}$
So, by putting all given data in the formula of molar conductance:
Molar conductance (${{\Lambda }_{m}}$) = $\dfrac{\kappa \times 1000}{C}$
= $\dfrac{1.061\times {{10}^{-4}}\times 1000}{0.01}$
= 10.61 $Sc{{m}^{2}}mo{{l}^{-1}}$
So, the correct answer is the option “C”.
Note: Here, Siemens(S) is the derived unit of electric conductance. So, here we should be careful about the given units, data and which formula we will use. Instead of giving direct specific conductance, cell constant and resistance can be given. If given then by applying the formula of specific conductance we can find its value.
Step by step solution:
We know that, the molar conductance is denoted by lambda (${{\Lambda }_{m}}$) and its unit is $Sc{{m}^{2}}mo{{l}^{-1}}$. Specific conductance is represented by kappa ($\kappa $) and its unit is S/m. Here S is Siemens. And the formulas of molar conductance and specific conductance are:
Specific conductance ($\kappa $) = cell constant / resistance
Molar conductance (${{\Lambda }_{m}}$) = specific conductance x 1000 / C
= \[\dfrac{\kappa \times 1000}{C}\]
Where, C is the molarity
Given,
Molarity = 0.01 M,
Specific conductance = $1.061\times {{10}^{-4}}$
So, by putting all given data in the formula of molar conductance:
Molar conductance (${{\Lambda }_{m}}$) = $\dfrac{\kappa \times 1000}{C}$
= $\dfrac{1.061\times {{10}^{-4}}\times 1000}{0.01}$
= 10.61 $Sc{{m}^{2}}mo{{l}^{-1}}$
So, the correct answer is the option “C”.
Note: Here, Siemens(S) is the derived unit of electric conductance. So, here we should be careful about the given units, data and which formula we will use. Instead of giving direct specific conductance, cell constant and resistance can be given. If given then by applying the formula of specific conductance we can find its value.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

The computer jargonwwww stands for Aworld wide web class 12 physics CBSE

State the principle of an ac generator and explain class 12 physics CBSE

