The Slowest animal ever discovered on earth is a crab found in the Red Sea that travels with an average speed of $5.7km/year$. How long will it take this crab to travel a distance of 1 meter? (In minutes)
A) 90
B) 91
C) 92
D) 93
Answer
599.1k+ views
Hint
We have given the speed of crab and need to find time to travel the given distance. We know time taken is given by division of speed and distance covered. We need to find time in minutes and given distance is in meters then we convert units of speed into $m/\min $.
Complete step by step solution
The speed of the crab is $5.7km/year$ and we need to convert it into $m/\min $. We know in one kilo-meter there are 1000 meters and in one year there are 365 days and in one day, there are 24 hours and in one hour, there are 60 minutes. Then speed of crab in $m/\min $ is-
$5.7 \times \dfrac{{1000}}{{365 \times 24 \times 60}} = \dfrac{{5700}}{{365 \times 24 \times 60}}n/\min $.
Time taken by crab to cover a displacement of 1 meter is
$Time = \dfrac{{displacement}}{{speed}} = \dfrac{{365 \times 24 \times 60}}{{5700}}$
$Time = 92.21 \simeq 92\min $.
Hence the time taken by a crab to travel 1 meter is 92 minutes.
Hence correct answer is option (C).
Note
In leap years there are 366 days but most of the years are non-leap years that’s why we take there are 356 in a year. Sometimes we don’t take care of units due to which we may get the wrong answer. If we need to find time in seconds, we just multiply time in minutes by 60.
We have given the speed of crab and need to find time to travel the given distance. We know time taken is given by division of speed and distance covered. We need to find time in minutes and given distance is in meters then we convert units of speed into $m/\min $.
Complete step by step solution
The speed of the crab is $5.7km/year$ and we need to convert it into $m/\min $. We know in one kilo-meter there are 1000 meters and in one year there are 365 days and in one day, there are 24 hours and in one hour, there are 60 minutes. Then speed of crab in $m/\min $ is-
$5.7 \times \dfrac{{1000}}{{365 \times 24 \times 60}} = \dfrac{{5700}}{{365 \times 24 \times 60}}n/\min $.
Time taken by crab to cover a displacement of 1 meter is
$Time = \dfrac{{displacement}}{{speed}} = \dfrac{{365 \times 24 \times 60}}{{5700}}$
$Time = 92.21 \simeq 92\min $.
Hence the time taken by a crab to travel 1 meter is 92 minutes.
Hence correct answer is option (C).
Note
In leap years there are 366 days but most of the years are non-leap years that’s why we take there are 356 in a year. Sometimes we don’t take care of units due to which we may get the wrong answer. If we need to find time in seconds, we just multiply time in minutes by 60.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

