
The Slowest animal ever discovered on earth is a crab found in the Red Sea that travels with an average speed of $5.7km/year$. How long will it take this crab to travel a distance of 1 meter? (In minutes)
A) 90
B) 91
C) 92
D) 93
Answer
567.6k+ views
Hint
We have given the speed of crab and need to find time to travel the given distance. We know time taken is given by division of speed and distance covered. We need to find time in minutes and given distance is in meters then we convert units of speed into $m/\min $.
Complete step by step solution
The speed of the crab is $5.7km/year$ and we need to convert it into $m/\min $. We know in one kilo-meter there are 1000 meters and in one year there are 365 days and in one day, there are 24 hours and in one hour, there are 60 minutes. Then speed of crab in $m/\min $ is-
$5.7 \times \dfrac{{1000}}{{365 \times 24 \times 60}} = \dfrac{{5700}}{{365 \times 24 \times 60}}n/\min $.
Time taken by crab to cover a displacement of 1 meter is
$Time = \dfrac{{displacement}}{{speed}} = \dfrac{{365 \times 24 \times 60}}{{5700}}$
$Time = 92.21 \simeq 92\min $.
Hence the time taken by a crab to travel 1 meter is 92 minutes.
Hence correct answer is option (C).
Note
In leap years there are 366 days but most of the years are non-leap years that’s why we take there are 356 in a year. Sometimes we don’t take care of units due to which we may get the wrong answer. If we need to find time in seconds, we just multiply time in minutes by 60.
We have given the speed of crab and need to find time to travel the given distance. We know time taken is given by division of speed and distance covered. We need to find time in minutes and given distance is in meters then we convert units of speed into $m/\min $.
Complete step by step solution
The speed of the crab is $5.7km/year$ and we need to convert it into $m/\min $. We know in one kilo-meter there are 1000 meters and in one year there are 365 days and in one day, there are 24 hours and in one hour, there are 60 minutes. Then speed of crab in $m/\min $ is-
$5.7 \times \dfrac{{1000}}{{365 \times 24 \times 60}} = \dfrac{{5700}}{{365 \times 24 \times 60}}n/\min $.
Time taken by crab to cover a displacement of 1 meter is
$Time = \dfrac{{displacement}}{{speed}} = \dfrac{{365 \times 24 \times 60}}{{5700}}$
$Time = 92.21 \simeq 92\min $.
Hence the time taken by a crab to travel 1 meter is 92 minutes.
Hence correct answer is option (C).
Note
In leap years there are 366 days but most of the years are non-leap years that’s why we take there are 356 in a year. Sometimes we don’t take care of units due to which we may get the wrong answer. If we need to find time in seconds, we just multiply time in minutes by 60.
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