
The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of the garden. [Length of rectangle is \[20 - (3.5 + 3.5)\]metres]
Answer
591.9k+ views
Hint: We will firstly find the length and the breadth of the rectangle. With the help of these values, we will have to find the areas of the rectangle and the semi-circle separately and add them. Finally, we are going to calculate the circumference of the semi-circles to find the perimeter of the garden.
Complete step by step Answer :
Looking at the question, we know that we are given the breadth of the garden and the length of the garden.
The breadth of the rectangle is equal to the diameter of the semicircle as they share the boundaries.
So, the breadth of the rectangle=the diameter of the semi-circle\[ = 7m\]
Hence, the radius of the semicircle\[ = \dfrac{7}{2} = 3.5m\]
The length of the rectangular part of the garden\[ = 20 - (3.5 + 3.5) = 20 - 7 = 13m\]
Area of the rectangular part of the garden\[ = l \times b = 13m \times 7m = 91{m^2}\]
We know that if we combine two semi-circles, we get a full circle.
So, the area of the circle with radius \[3.5m\]
\[
= \pi {r^2} = \dfrac{{22}}{7} \times {(3.5)^2} \\
= \dfrac{{22}}{7} \times 3.5 \times 3.5 \\
= 22 \times 3.5 \times 0.5 \\
= 38.5{m^2} \\
\]
Perimeter of the circular part\[ = 2\pi r = 2 \times \dfrac{{22}}{7} \times 3.5 = 2 \times 22 \times 0.5 = 22m\]
Therefore, the perimeter of the garden
=the sum of the perimeter of both the semicircles and the length of the rectangle on both sides
=the sum of the perimeter of the circle and the length of the rectangle on both sides
\[
= 22 + 13 \times 2 \\
= 22 + 26 \\
= 48m \\
\]
The area of the garden= the sum of the area of the rectangle and the area of the semicircles
= the sum of the area of the rectangle and the area of the circle
\[
= 38.5 + 91 \\
= 129.5{m^2} \\
\]
Therefore, the area and the perimeter of the garden is \[129.5{m^2}\& 48m\] respectively.
Note: We will have to remember all the mensuration formulas for all the figures. We might make the mistake of adding the perimeter of the rectangle with the perimeter of the circle but we have to remember that we are asked to find the perimeter or the boundary of the garden which does not include the breadth of the rectangle or the diameter of the semicircles.
Complete step by step Answer :
Looking at the question, we know that we are given the breadth of the garden and the length of the garden.
The breadth of the rectangle is equal to the diameter of the semicircle as they share the boundaries.
So, the breadth of the rectangle=the diameter of the semi-circle\[ = 7m\]
Hence, the radius of the semicircle\[ = \dfrac{7}{2} = 3.5m\]
The length of the rectangular part of the garden\[ = 20 - (3.5 + 3.5) = 20 - 7 = 13m\]
Area of the rectangular part of the garden\[ = l \times b = 13m \times 7m = 91{m^2}\]
We know that if we combine two semi-circles, we get a full circle.
So, the area of the circle with radius \[3.5m\]
\[
= \pi {r^2} = \dfrac{{22}}{7} \times {(3.5)^2} \\
= \dfrac{{22}}{7} \times 3.5 \times 3.5 \\
= 22 \times 3.5 \times 0.5 \\
= 38.5{m^2} \\
\]
Perimeter of the circular part\[ = 2\pi r = 2 \times \dfrac{{22}}{7} \times 3.5 = 2 \times 22 \times 0.5 = 22m\]
Therefore, the perimeter of the garden
=the sum of the perimeter of both the semicircles and the length of the rectangle on both sides
=the sum of the perimeter of the circle and the length of the rectangle on both sides
\[
= 22 + 13 \times 2 \\
= 22 + 26 \\
= 48m \\
\]
The area of the garden= the sum of the area of the rectangle and the area of the semicircles
= the sum of the area of the rectangle and the area of the circle
\[
= 38.5 + 91 \\
= 129.5{m^2} \\
\]
Therefore, the area and the perimeter of the garden is \[129.5{m^2}\& 48m\] respectively.
Note: We will have to remember all the mensuration formulas for all the figures. We might make the mistake of adding the perimeter of the rectangle with the perimeter of the circle but we have to remember that we are asked to find the perimeter or the boundary of the garden which does not include the breadth of the rectangle or the diameter of the semicircles.
Recently Updated Pages
Which cell organelles are present in white blood C class 11 biology CBSE

What is the molecular geometry of BrF4 A square planar class 11 chemistry CBSE

How can you explain that CCl4 has no dipole moment class 11 chemistry CBSE

Which will undergo SN2 reaction fastest among the following class 11 chemistry CBSE

The values of mass m for which the 100 kg block does class 11 physics CBSE

Why are voluntary muscles called striated muscles class 11 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

Show that total energy of a freely falling body remains class 11 physics CBSE

