
The reaction of sodium thiosulphate with $ {{I}_{2}} $ :
(This question has multiple correct options.)
(A) Sodium sulphite
(B) Sodium sulphate
(C) Sodium iodide
(D) Sodium tetrathionate
Answer
549.9k+ views
Hint: We need to write down the correct reaction. Sodium thiosulphate reacts with $ {{I}_{2}} $ to give two products. Thus, there are two correct options in the above question. One product contains iodine and the other contains oxygen and sulphur.
Complete step by step solution:
The reaction occurs between sodium thiosulphate having chemical formula $ \text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}} $ and iodine $ {{I}_{2}} $ .
So, the reaction can be written as:
$ 2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\to 2NaI+N{{a}_{2}}{{S}_{4}}{{O}_{6}} $
The products obtained in the above reaction are sodium iodide $ NaI $ and sodium tetrathionate $ N{{a}_{2}}{{S}_{4}}{{O}_{6}} $
So, we need to see from the above options, and select the correct value.
Thus, the correct answer is option C and D.
Additional Information
We should know that there are two forms of iodine, elemental diatomic iodine and ionic monoatomic iodide. Elemental iodine, consists of two iodine atoms covalently bound together.
Note:
Iodine is used to treat and prevent iodine deficiency and as an antiseptic. For iodine deficiency it can be given by mouth or injection into a muscle. As an antiseptic it may be used on wounds that are wet or to disinfect the skin before surgery.
On other hand sodium iodide is an ionic compound formed from the chemical reaction of sodium metal and iodine. Under standard conditions, it is a white, water-soluble solid comprising a 1:1 mix of sodium cations and iodide anions in a crystal lattice.
Sodium iodide is a water-soluble ionic compound with a crystal lattice. Sodium iodide is a source of iodine and can be administered as a supplement for total parenteral nutrition but is more commonly used in veterinary medicine.
Complete step by step solution:
The reaction occurs between sodium thiosulphate having chemical formula $ \text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}} $ and iodine $ {{I}_{2}} $ .
So, the reaction can be written as:
$ 2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\to 2NaI+N{{a}_{2}}{{S}_{4}}{{O}_{6}} $
The products obtained in the above reaction are sodium iodide $ NaI $ and sodium tetrathionate $ N{{a}_{2}}{{S}_{4}}{{O}_{6}} $
So, we need to see from the above options, and select the correct value.
Thus, the correct answer is option C and D.
Additional Information
We should know that there are two forms of iodine, elemental diatomic iodine and ionic monoatomic iodide. Elemental iodine, consists of two iodine atoms covalently bound together.
Note:
Iodine is used to treat and prevent iodine deficiency and as an antiseptic. For iodine deficiency it can be given by mouth or injection into a muscle. As an antiseptic it may be used on wounds that are wet or to disinfect the skin before surgery.
On other hand sodium iodide is an ionic compound formed from the chemical reaction of sodium metal and iodine. Under standard conditions, it is a white, water-soluble solid comprising a 1:1 mix of sodium cations and iodide anions in a crystal lattice.
Sodium iodide is a water-soluble ionic compound with a crystal lattice. Sodium iodide is a source of iodine and can be administered as a supplement for total parenteral nutrition but is more commonly used in veterinary medicine.
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