The reaction conditions leading to the best yield of ${C_2}{H_5}Cl$ are:
A) $\,{C_2}{H_6}\left( {excess} \right) + C{l_2} \to \,$
B) $\,{C_2}{H_6} + C{l_2} \to \,$
C) $\,{C_2}{H_6} + C{l_2}\left( {excess} \right) \to \,$
D) None of these
Answer
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Hint: Halogenation of an alkane produces a hydrocarbon derivative during which one or more halogen atoms are substituted for hydrogen atoms. Alkanes are known as notoriously unreactive compounds because they are non-polar and lack functional groups at which reactions can occur. Atom halogenation, therefore, provides a way by which alkanes will be functionalized.
Complete step by step answer:
Alkane halogenation is an example of a substitution reaction, a kind of reaction that usually occurs in the field of chemistry.
Halogenation of alkanes will cause the formation of a Haloalkane.
During this reaction, if we use chlorine in excess, then dichloro and trichloro forms as a product and if ethane is employed in excess, ethyl chloride will be formed as a major product.
So, the reaction takes place as follows:
${C_2}{H_6}(excess) + C{l_2} \to {C_2}{H_5}Cl + HCl\,$
The reaction does not stop at this step, however, because the chlorinated ethane product can react with the additional chlorine to produce polychlorinated products.
A severe limitation of the radical halogenation however is the number of similar $C - H$ bonds that are present in all but the simplest alkanes, so selective reactions are difficult to achieve.
So, the correct answer is Option A .
Note: A substitution reaction may be a reaction within which a part of a tiny low reacting molecule replaces an atom or a gaggle of atoms on a hydrocarbon or hydrocarbon derivative.The notation $R - H$ could be a general formula for an alkane. $R$ during this case represents a radical. The addition of an atom to a group produces the parent hydrocarbon of the alkyl. The notation $R - X$ on the merchandise side is that the general formula for a halogenated alkane. $X$ is the general symbol for a halogen atom. Reaction conditions are noted by placing these conditions on the equation arrow that separates reactants from products. Halogenation of an alkane requires the presence of warmth or light.
Complete step by step answer:
Alkane halogenation is an example of a substitution reaction, a kind of reaction that usually occurs in the field of chemistry.
Halogenation of alkanes will cause the formation of a Haloalkane.
During this reaction, if we use chlorine in excess, then dichloro and trichloro forms as a product and if ethane is employed in excess, ethyl chloride will be formed as a major product.
So, the reaction takes place as follows:
${C_2}{H_6}(excess) + C{l_2} \to {C_2}{H_5}Cl + HCl\,$
The reaction does not stop at this step, however, because the chlorinated ethane product can react with the additional chlorine to produce polychlorinated products.
A severe limitation of the radical halogenation however is the number of similar $C - H$ bonds that are present in all but the simplest alkanes, so selective reactions are difficult to achieve.
So, the correct answer is Option A .
Note: A substitution reaction may be a reaction within which a part of a tiny low reacting molecule replaces an atom or a gaggle of atoms on a hydrocarbon or hydrocarbon derivative.The notation $R - H$ could be a general formula for an alkane. $R$ during this case represents a radical. The addition of an atom to a group produces the parent hydrocarbon of the alkyl. The notation $R - X$ on the merchandise side is that the general formula for a halogenated alkane. $X$ is the general symbol for a halogen atom. Reaction conditions are noted by placing these conditions on the equation arrow that separates reactants from products. Halogenation of an alkane requires the presence of warmth or light.
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