Question

The reaction $C{H_3}COOH + {C_2}{H_5}OH \to C{H_3}COO{C_2}{H_5} + {H_2}O$  can be made to proceed in the forward direction by:
A.Increasing temperature
B.Sudden cooling of the reaction mixture
C.Conducting the reaction in the presence of a small quantity of $NaOH$
D.Taking excess of ${C_2}{H_5}OH$ and $C{H_3}COOH$

Answer 1

Hint: To proceed a reaction into forwarding direction there are different types of possible properties we can use, sometimes increasing temperature helps the reactant to react faster as their energy increases or adding a catalyst also works in some cases.

Complete step by step solution: In the reaction given above, we can see that two reactants that are reacted with each other are acetic acid and ethanol which results in the formation of methoxy ethane and water. In this reaction we can observe that there are no external compound or other factors such as heat or catalyst are used during the reaction taken place, so if we add more of the reactant in the system there will be an increase in the amount of the reactants which will be automatically balanced by forming more products that are methoxy ethane and water which means the rate of the forward reaction increases. This types of the addition of reactant or product to either side of the reaction are known as common ion effect due to addition of excess common element the substance on the one side of the reaction increases resulting in the balancing out of the reaction, the reaction carries in the direction of higher substance to the lower substance or can be said as the higher potential to lower potential.

Note: In the event that the temperature is expanded for an endothermic response, basically a reactant is being added, so the harmony shifts toward items. Diminishing the temperature is identical to diminishing a reactant (for endothermic responses) or an item (for exothermic responses), and the harmony moves appropriately.