Question

The ratio of the prices of a bicycle and a motorbike is $ 8:75 $ . If the price of the cycle is $ Rs.4800 $ . What is the price of the motorbike?

Answer 1

Hint: First we have to define what the terms we need to solve the problem are.
Since the ratio is the relation between two terms or values that shows the number of times one value will be contained or else is contained within the other values.
Let the bicycle ratio be given as eight is less than the motorbike ratio is seventy-five.
Also, the price of the cycle is given as $ Rs.4800 $ .

Complete step by step answer:
First, let us fix the unknown ratio to be X(price); so that we can apply this to the equation form and find the value required. So let the ratio be X; then we are converting the given terms as bicycle price is $ 8x $ and then also the motorbike price is $ 75x $ .
Since the price of the bicycle is given as $ Rs.4800 $ ; hence converting the values into an equation.
Thus, we get $ 8x = 4800 $ (the price and ratio of the bicycle is combined).
Further solving the equation, we get $ 8x = 4800 \Rightarrow x = 600 $ (on applying the canceling the common terms).
Thus, we get the value of the X is six hundred, which is the common ratio between the bicycle and motorbike.
Hence applying the value of the X into the ratio of the motorbike, we get $ 75x \Rightarrow 75(600) $ .
Now simplifying the equation with multiplication, we get $ 45000 $
Hence, the price of the motorbike is $ Rs.45000 $.

Note: since the ratio is the difference between the two values like bicycle and motorbike is $ 8:75 $ .
The price of the bicycle is $ Rs.4800 $ and the price of the motorbike is $ Rs.45000 $ ; thus, if we cancel each other, we get the same ratio as given in the problem.
And $ 600 $ is a common difference.