The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is?
A- 2: -1
B- 1:1
C- 1: -2
D- 1: -1
Answer
607.8k+ views
Hint: Bohr orbit refers to the orbit in which the electron revolves around the nucleus of the hydrogen atom. That orbit is considered to be circular for easy calculations although the orbit is elliptical in shape. The orbit is a stationary orbit.
Complete step by step answer:
A good analogy of movement of electrons around the nucleus in orbit is the movement of satellites around the earth. The total energy is negative and that is why the satellite/electrons remain bound in the circular orbit.
The relation between kinetic energy, Potential energy, and Total energy for the electron is given as
-TE=KE=-PE/2------(1)
Here TE represents total energy, KE represents kinetic energy and PE represents potential energy.
So, from equation (1) the ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom,
\[\dfrac{KE}{TE}=1:-1\]
So, the correct answer is “Option D”.
Additional Information:
The Bohr model states that electrons in atoms move in circular orbits around the nucleus and they do so in certain fixed circular orbits at a discrete set of distances from the nucleus. In these orbits they do not radiate energy.
Note:
In moving in these stationary orbits they can jump to higher orbits by absorbing energy and can jump back to lower orbits by emission of energy. Planck radiation formula gives the relationship between the energy absorbed.
Complete step by step answer:
A good analogy of movement of electrons around the nucleus in orbit is the movement of satellites around the earth. The total energy is negative and that is why the satellite/electrons remain bound in the circular orbit.
The relation between kinetic energy, Potential energy, and Total energy for the electron is given as
-TE=KE=-PE/2------(1)
Here TE represents total energy, KE represents kinetic energy and PE represents potential energy.
So, from equation (1) the ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom,
\[\dfrac{KE}{TE}=1:-1\]
So, the correct answer is “Option D”.
Additional Information:
The Bohr model states that electrons in atoms move in circular orbits around the nucleus and they do so in certain fixed circular orbits at a discrete set of distances from the nucleus. In these orbits they do not radiate energy.
Note:
In moving in these stationary orbits they can jump to higher orbits by absorbing energy and can jump back to lower orbits by emission of energy. Planck radiation formula gives the relationship between the energy absorbed.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Name the crygenes that control cotton bollworm and class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Ribosomal RNA is actively synthesised in A Nucleoplasm class 12 biology CBSE

How many molecules of ATP and NADPH are required information class 12 biology CBSE

