
The radius of the director circle of the hyperbola$\dfrac{{{x^2}}}{{a\left( {a + 4b} \right)}} - \dfrac{{{y^2}}}{{b\left( {2a - b} \right)}} = 1;{\text{ }}2a > b > 0$ is:
A.${a^2} + {b^2} + 4ab$
B.$a + b$
C.${a^2} + {b^2} + 2ab$
D.$2{\left( {a + b} \right)^2}$
Answer
596.4k+ views
Hint: It is known that the director of a hyperbola is the locus of the point of intersection of two perpendicular tangents to that given hyperbola, whose general equation is given by, ${x^2} + {y^2} = {a^2} - {b^2}$. Thus, all you need to do to find the radius of the director circle is compare the standard equation of the director circle, with the general equation of the circle.
Complete step-by-step answer:
Let us begin with considering the given equation of the hyperbola,
$\dfrac{{{x^2}}}{{a\left( {a + 4b} \right)}} - \dfrac{{{y^2}}}{{b\left( {2a - b} \right)}} = 1;{\text{ }}2a > b > 0$
The equation of the director circle of any general hyperbola is given by;
${x^2} + {y^2} = {a^2} - {b^2}$
Here, instead of ${a^2}$ we have $a\left( {a + 4b} \right)$ and instead of ${b^2}$ we have $b\left( {2a - b} \right)$.
${x^2} + {y^2} = a\left( {a + 4b} \right) - b\left( {2a - b} \right)$
Simplify the right-hand side of the obtained equation of the direction circle.
$ {x^2} + {y^2} = {a^2} + 4ab - 2ab + {b^2} \\
= {a^2} + {b^2} + 2ab \\
$
Now, using the formula, ${\left( {r + s} \right)^2} = {r^2} + {s^2} + 2rs$ to simplify the obtained equation further.
${x^2} + {y^2} = {\left( {a + b} \right)^2}......(1)$
Now, it is known that the standard equation of the circle is given by;
${x^2} + {y^2} = {r^2}......(2)$
Let us compare the equation (1) and (2) to find the radius of the director circle for the given hyperbola.
$
{r^2} = {\left( {a + b} \right)^2} \\
\Rightarrow r = a + b \\
$
Hence, the radius of the director circle for the given equation of hyperbola is $a + b$. Thus, you can mark option (B) as your correct option.
Note: In order to solve these types of problems or find any particular equations, you should be thorough with the definitions and the standard formula of the conics involved in the question. Like in this question you need to have a good understanding of the standard forms of equations of hyperbola, director circle and the circle. Also, if at all you do not remember the formula then you can also use the method to find the locus of points that form the required director circle. But here you may go wrong in finding the locus, so the best way is to get familiar with the standard terms and equations of conics.
Complete step-by-step answer:
Let us begin with considering the given equation of the hyperbola,
$\dfrac{{{x^2}}}{{a\left( {a + 4b} \right)}} - \dfrac{{{y^2}}}{{b\left( {2a - b} \right)}} = 1;{\text{ }}2a > b > 0$
The equation of the director circle of any general hyperbola is given by;
${x^2} + {y^2} = {a^2} - {b^2}$
Here, instead of ${a^2}$ we have $a\left( {a + 4b} \right)$ and instead of ${b^2}$ we have $b\left( {2a - b} \right)$.
${x^2} + {y^2} = a\left( {a + 4b} \right) - b\left( {2a - b} \right)$
Simplify the right-hand side of the obtained equation of the direction circle.
$ {x^2} + {y^2} = {a^2} + 4ab - 2ab + {b^2} \\
= {a^2} + {b^2} + 2ab \\
$
Now, using the formula, ${\left( {r + s} \right)^2} = {r^2} + {s^2} + 2rs$ to simplify the obtained equation further.
${x^2} + {y^2} = {\left( {a + b} \right)^2}......(1)$
Now, it is known that the standard equation of the circle is given by;
${x^2} + {y^2} = {r^2}......(2)$
Let us compare the equation (1) and (2) to find the radius of the director circle for the given hyperbola.
$
{r^2} = {\left( {a + b} \right)^2} \\
\Rightarrow r = a + b \\
$
Hence, the radius of the director circle for the given equation of hyperbola is $a + b$. Thus, you can mark option (B) as your correct option.
Note: In order to solve these types of problems or find any particular equations, you should be thorough with the definitions and the standard formula of the conics involved in the question. Like in this question you need to have a good understanding of the standard forms of equations of hyperbola, director circle and the circle. Also, if at all you do not remember the formula then you can also use the method to find the locus of points that form the required director circle. But here you may go wrong in finding the locus, so the best way is to get familiar with the standard terms and equations of conics.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

