Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

The product of two consecutive positive odd numbers is 195. Find the numbers.

seo-qna
SearchIcon
Answer
VerifiedVerified
486.9k+ views
Hint: Assume the numbers as some variables. Frame the equation using the condition given in the question and solve it.

As per the question, let the two positive consecutive odd numbers be $x - 1$ and $x + 1$.
The product of the numbers is given as 196. So, we have:
$ \Rightarrow \left( {x - 1} \right)\left( {x + 1} \right) = 195$
As we know that $\left( {x - a} \right)\left( {x + a} \right) = {x^2} - {a^2}$. Using this formula, we’ll get:
$
   \Rightarrow {x^2} - 1 = 195, \\
   \Rightarrow {x^2} = 196, \\
   \Rightarrow x = \pm \sqrt {196} , \\
   \Rightarrow x = \pm 14 \\
$
But we have to consider only positive integers, so we will ignore negative values. $x = 14$ is the valid solution.
$x - 1 = 13{\text{ and }}x + 1 = 15$
Therefore our numbers are 13 and 15.

Note: We can also assume numbers to be $x$ and $x + 2$. In that case, we will get a different quadratic equation but the end result will be the same.