Question

The product obtained in the reaction of \[C{H_3}CON{H_2}\] and $NaN{O_2}/HCl$ is –
(A).$C{H_3}COOH$
(B) $C{H_3}COC{H_3}$
(C) $C{H_3}CO\mathop N\limits^ \oplus {H_3}\mathop C\limits^{\left( - \right)} l$
(D) $C{H_3}N{H_2}$

Answer 1

Hint: Acetamide is an organic compound which releases nitrogen gas from the solution when reacted with $NaN{O_2}/HCl$.It is the simplest amide derived from acetic acid. It finds some use as a plasticizer and as an industrial solvent.

Complete step by step answer:
We know the given compound \[C{H_3}CON{H_2}\] commonly known as acetamide is a organic compound with structure as: -

It is the simplest amide with IUPAC name ethanamide and is derived from acetic acid by the reaction with ammonia
$C{H_3}COOH(Acetic{\text{ }}Acid){\text{ }} + {\text{ }}H - N{H_2}{\text{ }}(Ammonia){\text{ }} \to {\text{ }}C{H_3}CON{H_2}{\text{ }}(Ethanamide)$
In industries, acetamide is produced by dehydrating ammonium acetate or via hydration of acetonitrile.
i.e. $C{H_3}CN + {H_2}O \to C{H_3}CON{H_2}$
Ethanamide is used as a plasticizer and an industrial solvent. It has uses in electro chemistry and organic synthesis of pharmaceuticals, pesticides and antioxidants for plastics. When $C{H_3}CON{H_2}$ is reacted with $NaN{o_2}$ in the presence of $HCl$, we get $C{H_3}COOH$(acetic acid) as the main product.

Note:
Acetic acid will also be formed from ethanamide if the reagent is $HN{O_2}$. Moreover, when ethanamide is treated with water, it also yields acetic acid.
i.e. $C{H_3}CoN{H_2} + {H_2}O \to C{H_3}COOH + {H_2}O$