Question

The process $\Delta U=0$ for an ideal gas can be best represented in the form of a graph:
A.

B.

C.

D.

Answer 1

Hint: The study of thermodynamic processes is studied using the laws of thermodynamics. The relation of the change in internal energy of the system is mentioned in the ${{1}^{st}}$ law of thermodynamics. An ideal gas always obeys the law of ideal gas or ideal gas equation.
Formula to be used-
$PV=nRT$

Complete step by step solution:
When the change in the internal energy of a system is zero ($\Delta U=0$ ) the system is said to be an isolated system.
In the case of an isolated system, the temperature is always constant. It is known that the internal energy of a system is directly proportional to the temperature.
$U\propto Temp$
So, if the temperature is content the value of internal energy will be constant.
From the law of ideal gas, we know that,
$PV=nRT$
As in the case of the system mentioned in the question the temperature is constant. So, for this case, the ideal gas equation can be modified as
$PV=constant$
This can be rearranged as
$\begin{align}
  & P=\dfrac{contant}{V} \\
 & \Rightarrow P\propto \dfrac{1}{V} \\
\end{align}$
As the pressure is inversely proportional to the volume of the system. When the plot of internal pressure will be constructed concerning the volume of the system it will form a hyperbolic curve as shown a=in the graph here.

So, when we give a glance over the graphical representation mentioned in the question.

Hence, the correct option is Option B.

Note:
${{1}^{st}}$ law of thermodynamics is a reconstruction of the law of conservation of energy. According to the law of conservation the energy cannot be created or destroyed it can be transformed from one form to another. In the case of thermodynamic processes, heat is considered to be a form of energy. The thermodynamic equation gives a relation between the internal energy, supplied energy, and the work done by the system ( $\Delta U=Q-W$).