
The probability of certain event is
A. 0
B. 1
C. greater than 1
D. less than 0
Answer
611.7k+ views
Hint:- Take an example of tossing a coin and keep the event as getting an outcome ,Now calculate the probability of getting an outcome by adding the probability of all possible outcomes.
Complete step-by-step answer:
Let us take an example of coin toss.
As we know that the coins had two sides, head and tail.
So, there can be two possible outcomes head and tail.
As we know that according to the probability formula probability of occurring a favourable outcome is equal to the \[\dfrac{{{\text{Number of favourable Outcome}}}}{{{\text{Total number of outcomes}}}}\].
So, when the coin is tossed once. Then,
The probability of getting head = \[\dfrac{{\text{1}}}{2}\]
And, the probability of getting tail = \[\dfrac{{\text{1}}}{2}\]
But our main event is getting an outcome, it does not depend whether it is head or tail.
So, the probability of the main event should be equal to the probability of getting a head and the probability of getting a tail.
So, the probability of main event = \[\dfrac{{\text{1}}}{2}\] + \[\dfrac{{\text{1}}}{2}\] = 1
So, the probability of certain events should always be 1.
Hence, the correct option will be B.
Note:- Whenever we come up with this type of problem then we should remember the formula for calculating probability of getting any outcome and that is \[\dfrac{{{\text{Number of possible Outcome}}}}{{{\text{Total number of outcomes}}}}\]. And the probability of getting any outcome always lies between 0 and 1, because the minimum possible number of that outcome is zero and the maximum possible number of that outcome is equal to the total number of outcomes. And the probability of getting outcome (any outcome) is our main event main event and this is equal to the sum of probability of getting each element.
Complete step-by-step answer:
Let us take an example of coin toss.
As we know that the coins had two sides, head and tail.
So, there can be two possible outcomes head and tail.
As we know that according to the probability formula probability of occurring a favourable outcome is equal to the \[\dfrac{{{\text{Number of favourable Outcome}}}}{{{\text{Total number of outcomes}}}}\].
So, when the coin is tossed once. Then,
The probability of getting head = \[\dfrac{{\text{1}}}{2}\]
And, the probability of getting tail = \[\dfrac{{\text{1}}}{2}\]
But our main event is getting an outcome, it does not depend whether it is head or tail.
So, the probability of the main event should be equal to the probability of getting a head and the probability of getting a tail.
So, the probability of main event = \[\dfrac{{\text{1}}}{2}\] + \[\dfrac{{\text{1}}}{2}\] = 1
So, the probability of certain events should always be 1.
Hence, the correct option will be B.
Note:- Whenever we come up with this type of problem then we should remember the formula for calculating probability of getting any outcome and that is \[\dfrac{{{\text{Number of possible Outcome}}}}{{{\text{Total number of outcomes}}}}\]. And the probability of getting any outcome always lies between 0 and 1, because the minimum possible number of that outcome is zero and the maximum possible number of that outcome is equal to the total number of outcomes. And the probability of getting outcome (any outcome) is our main event main event and this is equal to the sum of probability of getting each element.
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