
The pressure and temperature of $4d{m^3}$ carbon dioxide gas are doubled. Then volume of carbon dioxide would be:
A: $2d{m^3}$
B: $3d{m^3}$
C: $4d{m^3}$
D: $8d{m^3}$
Answer
587.4k+ views
Hint:
There is an equation called the ideal gas equation. This equation relates pressure, volume, temperature and number of moles of gas with each other. With the help of this equation we can solve any problem related to temperature, volume and pressure of gas.
Formula used: $\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$
Where ${P_1},{V_1},{T_1}$ is initial pressure, temperature and volume of gas and ${P_2},{V_2},{T_2}$ is final pressure, temperature and volume of gas.
Complete step by step answer:
In this question the initial pressure and temperature of gas is doubled and we have to find the final volume of the gas. This can be found by using the ideal gas equation. This equation relates pressure, volume, temperature and number of moles of gas with each other. According to this equation,
$PV = nRT$
Where, $P$ is pressure, $V$ is volume, $n$ is number of moles, $R$ is gas constant and $T$ is temperature.
In this question we have changed the pressure and temperature of gas, and we have to find the effect on volume on changing these quantities. Therefore the number of moles and gas constant will remain the same before and after making the change. So, equation can be written as,
$\dfrac{{PV}}{T} = {\text{constant}}$
This means,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$ (Ratio before making changes is equal to ratio after making changes)
According to the question, ${P_2} = 2{P_1}$ and ${T_2} = 2{T_1}$. Substituting these values in the equation,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{2{P_1}{V_2}}}{{2{T_1}}}$
Solving this we get,
${V_1} = {V_2}$
This means the initial volume is equal to the final volume. Initial volume is $4d{m^3}$ (given) therefore final volume is also equal to $4d{m^3}$ (solved above).
So, the correct answer is option C.
Note:
Ideal gas equation is derived by taking some assumptions. Some of these assumptions are, the gas consists of a very large number of particles, which obey Newton's laws and are in random motion. Volume of the molecules is very small as compared to the volume occupied by the gas.
There is an equation called the ideal gas equation. This equation relates pressure, volume, temperature and number of moles of gas with each other. With the help of this equation we can solve any problem related to temperature, volume and pressure of gas.
Formula used: $\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$
Where ${P_1},{V_1},{T_1}$ is initial pressure, temperature and volume of gas and ${P_2},{V_2},{T_2}$ is final pressure, temperature and volume of gas.
Complete step by step answer:
In this question the initial pressure and temperature of gas is doubled and we have to find the final volume of the gas. This can be found by using the ideal gas equation. This equation relates pressure, volume, temperature and number of moles of gas with each other. According to this equation,
$PV = nRT$
Where, $P$ is pressure, $V$ is volume, $n$ is number of moles, $R$ is gas constant and $T$ is temperature.
In this question we have changed the pressure and temperature of gas, and we have to find the effect on volume on changing these quantities. Therefore the number of moles and gas constant will remain the same before and after making the change. So, equation can be written as,
$\dfrac{{PV}}{T} = {\text{constant}}$
This means,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$ (Ratio before making changes is equal to ratio after making changes)
According to the question, ${P_2} = 2{P_1}$ and ${T_2} = 2{T_1}$. Substituting these values in the equation,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{2{P_1}{V_2}}}{{2{T_1}}}$
Solving this we get,
${V_1} = {V_2}$
This means the initial volume is equal to the final volume. Initial volume is $4d{m^3}$ (given) therefore final volume is also equal to $4d{m^3}$ (solved above).
So, the correct answer is option C.
Note:
Ideal gas equation is derived by taking some assumptions. Some of these assumptions are, the gas consists of a very large number of particles, which obey Newton's laws and are in random motion. Volume of the molecules is very small as compared to the volume occupied by the gas.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

10 examples of friction in our daily life

