Questions & Answers

Question

Answers

A.29484

B.28696

C.24,579

D.30,184

Answer
Verified

Step 1:

We are given that at present the population is 25000.

Let us consider the present population to be ${P_1}$

${P_1} = 25000$

Now it is given that there is a population rise of 4% in the first year .

This is nothing other than 4% of ${P_1}$, people have increased.

So ,let's find the value of 4% of ${P_1}$,

$

\Rightarrow \dfrac{4}{{100}}*25000 = 4*250 \\

{\text{ }} = 1000 \\

$

Therefore there is a rise of 1000 people at the end of first year .

So now the population at the end of first year is ${P_1} + 1000$

Let the new population be${P_2}$

Therefore

$

{P_2} = {P_1} + 1000 = 25000 + 1000 = 26000 \\

\therefore {P_2} = 26000 \\

$

Step 2:

Now let's repeat the same process with ${P_2}$

Now it is given that there is a population rise of 5% in the second year .

This is nothing other than 5% of ${P_2}$, people have increased.

So ,let's find the value of 5% of ${P_2}$,

$

\Rightarrow \dfrac{5}{{100}}*26000 = 5*260 \\

{\text{ }} = 1300 \\

$

Therefore there is a rise of 1300 people at the end of second year when compared to the previous year.

So now the population at the end of second year is ${P_2} + 1300$

Let the new population be${P_3}$

Therefore

$

{P_3} = {P_2} + 1300 = 26000 + 1300 = 27300 \\

\therefore {P_3} = 27300 \\

$

Step 3:

Now let's repeat the same process with ${P_3}$

Now it is given that there is a population rise of 8% in the third year .

This is nothing other than 8% of ${P_3}$, people have increased.

So ,let's find the value of 8% of ${P_3}$,

$

\Rightarrow \dfrac{8}{{100}}*27300 = 8*273 \\

{\text{ }} = 2184 \\

$

Therefore there is a rise of 2184 people at the end of third year when compared to the previous year.

So now the population at the end of third year is ${P_3} + 2184$

Let the new population be${P_4}$

Therefore

$

{P_4} = {P_3} + 2184 = 27300 + 2184 = 29484 \\

\therefore {P_4} = 29484 \\

$

Therefore the population after three years is 29,484.

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