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**Hint:**First we have to know about altitude of a triangle. A line from a vertex of a triangle which is perpendicular to the opposite side of a triangle is known as altitude or height of a triangle. So, there are a total no. of three altitudes. Then, the point of concurrency is the intersection of or more lines at a point. Using this we can try to figure out the correct option.

**Complete step-by-step answer:**We can find the point of concurrency of three altitudes of triangles.

But, we know that the altitude of a triangle is a perpendicular drawn from a vertex to its opposite side. So, it is clear to us that there are three vertices, there will be a total of three altitudes in a triangle.

Let us suppose a $\vartriangle ABC$ having altitude AA’, BB’ and CC’ intersecting at a common point say O.

We also know that the point of concurrency of three altitudes of a triangle is called orthocentre.

Hence, the point O is the orthocentre of $\vartriangle ABC$ .

**Therefore, the correct option is (D).**

**Note:**Remember the other terms related to a triangle like incenter, circumcenter and centroid and their definition. So, you can easily solve this kind of solution. Also, remember that the point of concurrency means a point where all the lines, at least three intersect at a common point.

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