
The point at which the gravitational force acting on any mass is zero due to the Earth and the Moon system is
(The mass of the Earth is approximately 81 times the mass of the Moon and the distance between the Earth and the Moon is 3,85,000 km.)
A. 36,000 km from the Moon
B. 38,500 km from the Moon
C. 34,500 km from the Moon
D. 30,000 km from the Moon
Answer
572.4k+ views
Hint:We need to equate the expressions for the gravitational force on a mass due to earth and moon respectively. Assuming a distance x of a certain mass from earth and solving the expression for the unknown parameter x, we can get the required answer.
Formula used:
The expression for gravitational force is given as
$F = G\dfrac{{{m_1}{m_2}}}{{{r^2}}}$
Complete answer:
Let the point at which the gravitational force acting on any mass is zero due to the Earth and the Moon system be at a distance x from the centre of earth. A mass m is at the distance x from the centre of earth. If total distance between centre of earth and moon is d then its value is given as
$d = 385000{\text{ }}km$
Let M be the mass of the moon then according to given information, the mass of earth is 81M.
The gravitational force on mass m due to earth is given as
${F_E} = G\dfrac{{81Mm}}{{{x^2}}}$
Here G is known as the gravitational constant.
Similarly, the gravitational force on mass m due to moon is given as
${F_M} = G\dfrac{{Mm}}{{{{\left( {d - x} \right)}^2}}}$
For the gravitational force to be zero for mass m, the forces due to earth and moon must be equal and being in opposite directions they cancel each other.
Therefore, we can write,
${F_E} = {F_M}$
Inserting the value of these expressions we get
$
\Rightarrow G\dfrac{{81Mm}}{{{x^2}}} = G\dfrac{{Mm}}{{{{\left( {d - x} \right)}^2}}} \\
\Rightarrow \dfrac{{81}}{{{x^2}}} = \dfrac{1}{{{{\left( {d - x} \right)}^2}}} \\
\Rightarrow \dfrac{9}{x} = \dfrac{1}{{\left( {d - x} \right)}} \\
\Rightarrow 9\left( {d - x} \right) = x \\
\Rightarrow 9d - 9x = x \\
\Rightarrow 10x = 9d \\
\Rightarrow x = 0.9d \\
$
Substituting value of d we get,
$x = 346500km$
Distance from moon is
$d - x = 385000 - 346500 = 38500m$
So, the correct answer is “Option B”.
Note:
It should be noted that this point where gravitational force is zero is closer to the moon as compared to earth. This happens because the gravitational pull of earth is stronger than that of the moon due to which we need to go farther away from earth and closer to the moon in order to get this point where the two gravitational forces match and cancel each other.
Formula used:
The expression for gravitational force is given as
$F = G\dfrac{{{m_1}{m_2}}}{{{r^2}}}$
Complete answer:
Let the point at which the gravitational force acting on any mass is zero due to the Earth and the Moon system be at a distance x from the centre of earth. A mass m is at the distance x from the centre of earth. If total distance between centre of earth and moon is d then its value is given as
$d = 385000{\text{ }}km$
Let M be the mass of the moon then according to given information, the mass of earth is 81M.
The gravitational force on mass m due to earth is given as
${F_E} = G\dfrac{{81Mm}}{{{x^2}}}$
Here G is known as the gravitational constant.
Similarly, the gravitational force on mass m due to moon is given as
${F_M} = G\dfrac{{Mm}}{{{{\left( {d - x} \right)}^2}}}$
For the gravitational force to be zero for mass m, the forces due to earth and moon must be equal and being in opposite directions they cancel each other.
Therefore, we can write,
${F_E} = {F_M}$
Inserting the value of these expressions we get
$
\Rightarrow G\dfrac{{81Mm}}{{{x^2}}} = G\dfrac{{Mm}}{{{{\left( {d - x} \right)}^2}}} \\
\Rightarrow \dfrac{{81}}{{{x^2}}} = \dfrac{1}{{{{\left( {d - x} \right)}^2}}} \\
\Rightarrow \dfrac{9}{x} = \dfrac{1}{{\left( {d - x} \right)}} \\
\Rightarrow 9\left( {d - x} \right) = x \\
\Rightarrow 9d - 9x = x \\
\Rightarrow 10x = 9d \\
\Rightarrow x = 0.9d \\
$
Substituting value of d we get,
$x = 346500km$
Distance from moon is
$d - x = 385000 - 346500 = 38500m$
So, the correct answer is “Option B”.
Note:
It should be noted that this point where gravitational force is zero is closer to the moon as compared to earth. This happens because the gravitational pull of earth is stronger than that of the moon due to which we need to go farther away from earth and closer to the moon in order to get this point where the two gravitational forces match and cancel each other.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

What are porins class 11 biology CBSE

Why is steel more elastic than rubber class 11 physics CBSE

Differentiate between red algae and brown algae class 11 biology CBSE

What is boron A Nonmetal B Metal C Metalloid D All class 11 chemistry CBSE

