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The pictograph given below gives the weekly sale of milk from a mother dairy outlet in Delhi.

DAYSSALES
SUNDAY
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MONDAY
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TUESDAY
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WEDNESDAY
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THURSDAY
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FRIDAY
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SATURDAY
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Scale:
100 litre =
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50 litre =
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(a) Calculate the total milk sold during the week. If it costs Rupees 32 per litre; calculate the weekly sale.
(b) On which day was the sale maximum?
(c) What was the sale on Wednesday?
(d) On which two days was the sale minimum?

Answer
VerifiedVerified
509.4k+ views
Hint: Here we convert the pictorial representation of sales of milk on each day into numeric data by multiplying the number of times a full milk bottle is shown with the quantity of one full milk bottle and then adding the similar multiplication for half milk bottles wherever depicted in the pictorial representation.

Complete step-by-step answer:
From the pictorial representation we can calculate the amount of milk sold by a mother dairy outlet in Delhi on each day of the week.
Since, 1 full bottle of milk represents 100 litres of milk and half bottle of milk represents 50 litres of milk, we can use this to convert pictorial data to numeric data.
Quantity in one full milk bottle \[ = 100\]litre
Quantity in one half milk bottle \[ = 50\]litre
Sunday:
Number of full milk bottles in the data \[ = 5\]
Number of half milk bottles \[ = 0\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 5 \times 100 + 0 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[500\]litres.
Monday:
Number of full milk bottles in the data \[ = 4\]
Number of half milk bottles \[ = 0\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 4 \times 100 + 0 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[400\]litres.
Tuesday:
Number of full milk bottles in the data \[ = 3\]
Number of half milk bottles \[ = 1\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 3 \times 100 + 1 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[350\]litres.
Wednesday:
Number of full milk bottles in the data \[ = 4\]
Number of half milk bottles \[ = 1\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 4 \times 100 + 1 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[450\]litres.
Thursday:
Number of full milk bottles in the data \[ = 6\]
Number of half milk bottles \[ = 0\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 6 \times 100 + 0 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[600\]litres.
Friday:
Number of full milk bottles in the data \[ = 3\]
Number of half milk bottles \[ = 1\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 3 \times 100 + 1 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[350\]litres.
Saturday:
Number of full milk bottles in the data \[ = 4\]
Number of half milk bottles \[ = 0\]
Total milk sold \[ = \]number of full milk bottles \[ \times \]quantity of milk in one full bottle \[ + \]number of half milk bottles \[ \times \]quantity of milk in one half bottle.
\[ \Rightarrow \]Total milk sold \[ = 4 \times 100 + 0 \times 50\]
\[\therefore \]Total milk sold on Sunday is \[400\]litres.
(a) Total milk sold during the week is the sum of milk sold on all days of week
Total milk sold in a week \[ = \]Milk sold on Sunday \[ + \] Milk sold on Monday \[ + \]Milk sold on Tuesday \[ + \]Milk sold on Wednesday \[ + \]Milk sold on Thursday \[ + \]Milk sold on Friday \[ + \]Milk sold on Saturday
\[ \Rightarrow \]Total milk sold in a week \[ = (500 + 400 + 350 + 450 + 600 + 350 + 400)\]litres
\[ \Rightarrow \]Total milk sold in a week \[ = 3050\]litres
Now cost of one litre of milk is Rupees 32.
We calculate the weekly sale by multiplying total quantity of milk sold in a week with cost of one litre of milk.
\[\therefore \]Weekly sale \[ = 3050 \times 32\]
Calculating the product
\[\therefore \]Weekly sale \[ = 97,600\]
So, the weekly sale of milk is Rupees 97,600.
(b) We have to find on which day the sale was maximum.
Since, we have the quantities of milk sold on days of week as
Sunday: 500 litres
Monday: 400 litres
Tuesday: 350 litres
Wednesday: 450 litres
Thursday: 600 litres
Friday: 350 litres
Saturday: 400 litres
From looking at the data above we can say that the maximum quantity of milk was sold on Thursday i.e. 600 litres.
Therefore, the sale was maximum on Thursday.
(c) The sale on Wednesday is given by the quantity of milk sold on Wednesday multiplied by the cost of one litre of milk.
\[ \Rightarrow \]Sale on Wednesday \[ = 450 \times 32\]
Calculating the product
\[ \Rightarrow \]Sale on Wednesday \[ = 14,400\]
\[\therefore \]Sale on Wednesday is Rupees 14,400.
(d) The days which had minimum sale will be the days on which mother dairy outlets sold the minimum quantity of milk.
Since, we have the quantities of milk sold on days of week as
Sunday: 500 litres
Monday: 400 litres
Tuesday: 350 litres
Wednesday: 450 litres
Thursday: 600 litres
Friday: 350 litres
Saturday: 400 litres
From the data we see that the least quantity of milk sold is 350 litres which was sold on Tuesday and Friday.
So, the days having minimum sales are Tuesday and Friday.

Note: Students are likely to make mistakes while converting the pictorial data to numeric data if they don’t convert the data with the help of scale given. Many students just start the solution with the assumption of pictures only that a full milk bottle shows 1 litre and half milk bottle shows half litre of milk.