The perpendicular distance of a straight line \[12x + 5y = 7\] from the origin is given by
A.\[\dfrac{7}{{13}}\]
B.\[\dfrac{{12}}{{13}}\]
C.\[\dfrac{5}{{13}}\]
D.\[\dfrac{1}{{13}}\]
Answer
534.6k+ views
Hint: Given is the equation of a line of the form \[ax + by + c = 0\]. The perpendicular distance can be calculated with the help of a formula that calculates the distance between straight lines from the origin. We will use that formula.
Complete step-by-step answer:
Given the equation of line is,
\[12x + 5y = 7\]
It is of the form,
\[ax + by + c = 0\]
We know that the perpendicular distance is given by the formula,
\[\left| d \right| = \left| {\dfrac{c}{{\sqrt {{a^2} + {b^2}} }}} \right|\]
So on comparing the given equation with the standard equation we get a=12, b=5 and c=-7.
Putting these values in the formula,
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{\sqrt {{{12}^2} + {5^2}} }}} \right|\]
Taking the squares,
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{\sqrt {144 + 25} }}} \right|\]
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{\sqrt {169} }}} \right|\]
We know that 169 is the perfect square of 13. So, writing the number out of the root we get,
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{13}}} \right|\]
The modulus of the value above is,
\[\left| d \right| = \dfrac{7}{{13}}\]
This is the perpendicular distance of the line from the origin is given by, \[\left| d \right| = \dfrac{7}{{13}}\]
So, the correct answer is “Option A”.
Note: Note that the formula used is simply the way to solve this. Also sometimes in the problem we are asked to find the distance between two straight lines or the distance between a line and a point situated in the same plane. There are different formulas for finding different distances.
Complete step-by-step answer:
Given the equation of line is,
\[12x + 5y = 7\]
It is of the form,
\[ax + by + c = 0\]
We know that the perpendicular distance is given by the formula,
\[\left| d \right| = \left| {\dfrac{c}{{\sqrt {{a^2} + {b^2}} }}} \right|\]
So on comparing the given equation with the standard equation we get a=12, b=5 and c=-7.
Putting these values in the formula,
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{\sqrt {{{12}^2} + {5^2}} }}} \right|\]
Taking the squares,
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{\sqrt {144 + 25} }}} \right|\]
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{\sqrt {169} }}} \right|\]
We know that 169 is the perfect square of 13. So, writing the number out of the root we get,
\[\left| d \right| = \left| {\dfrac{{ - 7}}{{13}}} \right|\]
The modulus of the value above is,
\[\left| d \right| = \dfrac{7}{{13}}\]
This is the perpendicular distance of the line from the origin is given by, \[\left| d \right| = \dfrac{7}{{13}}\]
So, the correct answer is “Option A”.
Note: Note that the formula used is simply the way to solve this. Also sometimes in the problem we are asked to find the distance between two straight lines or the distance between a line and a point situated in the same plane. There are different formulas for finding different distances.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

How many of the following diseases can be studied with class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Which of the following enzymes is used for carboxylation class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

