Question

The perimeter of a rectangle is 24 inches, how do you find the dimensions if its length is 3 times greater than its width?

Answer 1

Hint: First, you need to write the formula for finding the perimeter of the rectangle which is 2 ( l+ b). Here we are given that the length is 3 times greater than its width. So you need to write it as l = 3b . Now substitute it in the formula of the perimeter to find the value of b as the perimeter is given to be 24 inches. Then using l = 3b, you can find the value of l.

Complete step by step solution:
Here is the complete step by step solution.
The first step we need to do is to write the formula for finding the perimeter of the rectangle which is
$\Rightarrow P = 2\left( l+b \right)$
Here we are given that the length is 3 times greater than its width. So we need to write it as l = 3b. So, now we substitute it in the perimeter equation. Therefore, we get
$\Rightarrow P = 2\left( 3b+b \right)$
But the perimeter I gave was 24 inches. So we get:
$\Rightarrow 24 = 8b$
$\Rightarrow b = 3$
To find the value of the l we use the equation
$\Rightarrow l = 3b$
Substtuting b as 3, we get the value of l as
$\Rightarrow l = 3 \times 3$
$\Rightarrow l = 9$

Therefore, we get the dimensions of the rectangle as length = 9 inches and breadth or width = 3 inches.

Note: You need to know the formulas of perimeter and area of different types so that it will be easy when you get these kinds of questions. You also need to remember to write the units at the end. Here we need to write inches at the end.