Question

The percent of pure gold in 14 carat gold is about 58.3 %. A 14 carat gold ring weighs 7.6 grams. How many grams of pure gold are in the ring?

Answer 1

Hint: We have been given the weight of a 14 carat gold ring and the presence of the percentage of pure gold in the same. We can calculate this percentage on the weight by their product and obtain the required answer.

Complete step by step solution:
The percentage of pure iron (P) in 14 carat gold is given to be 58.3%.
P = 58.3 %
$ \Rightarrow P = \dfrac{{58.3}}{{100}}$ (In fraction)
The weight (W) of the 14 carat gold is given to be 7.6 grams.
🡪 W = 7.6 g
Both the quantities are given for 14 carat gold and the grams of the pure gold present are also to be calculated for the same. This can be given by the product of the two. So, the presence pure of pure gold (G) in grams is given as:
$\Rightarrow G = P \times W$
Substituting the values, we get:
$
\Rightarrow G = \dfrac{{58.3}}{{100}} \times 7.6{\text{ }}g \\
\Rightarrow G = 4.43g \;
 $
Therefore, the pure gold present in the ring in grams is equal to 4.43 g.
So, the correct answer is “4.43g”.

Note: Percentage means a part per 100 and thus is represented as a fraction of 100. The percentages are represented with the sign ‘%’ and are dimensionless.
The weight of the ring was given in grams and the amount of pure gold present was also asked in grams, so we didn’t do conversions. If the weight would have been given in higher or lower values, we ought to do the conversions then.