Question

The parking charges of a car at New Delhi Railway station for the first two hours are Rs 50 and Rs 10 for subsequent hours, write down an equation and find the charges for 6 hours.

Answer 1

Hint: The main hint for this question is that we will first consider the total number of hours to be x and total number of charges to be y. Since the charges for the first two hours are given. We will calculate the remaining hours as (total hours - 2) i.e. x-2. On the basis of this we will calculate the charges for the remaining hours to be (x-2) multiplied by the charges for the remaining hours which is Rs. 10. Then we will use the unitary method and compare the total charges y to the sum of charges of first two hours i.e. Rs. 50 and charges for the remaining hours which is Rs. 10 multiplied with (x-2). On the basis of this we will get the equation and then we will just calculate the charges for 6 hours by putting x=6 in the equation.

Complete step-by-step answer:
Let’s assume the total number of hours to be $x$ and the total number of charges be $y$
Charges for the first two hours is Rs.50 and the Charges for the left-out hours after that is Rs.10 (Given)
Remaining Hours = Total Hours-2
So Remaining Hours are equal to $x - 2$
So, Total charges for the remaining Hours = Rs. $10(x - 2)$
Total Charges= Charge for first 2 hours + Charge for remaining hours
$y = 50 + 10(x - 2)$
Hence, the equation is $y = 30 + 10x$ -------(1)
Now, we have to calculate the charges for 6 hours i.e. $x = 6$
On putting the value of x in the equation (1), we get
$y = 30 + 10 \times 6$
$y = 90$
Hence, the Parking Charges for the 6 hours is Rs.90

Note: In such questions, just understand the relationship among the constraints and make the equations as according to them and then you can just calculate the values as the equation will consist of variables dependent on each other say x and y here.