Question

The outer measurements of a closed wooden box are \[45cm \times 32cm \times 28cm\], if the box is made of wood 1 cm thick, the capacity of the box is:

Answer 1

Hint: Volume of a cuboid is \[length \times width \times height\]. Whatever be the thickness of the box is , this thickness will not add up to the capacity or volume of the box.

Complete step-by-step answer:
Given, Length of the box= 45cm
Width of the box= 32 cm
Height of the box = 28 cm
Also, the box is made up of wood 1 cm thick. This thickness will not add up to the capacity of the box.
Modified length of the box\[ = {\text{ }}45cm - 1cm{\text{ }} = 44{\text{ }}cm.\]
Modified width of the box \[ = 32cm - 1cm{\text{ }} = 31{\text{ }}cm.\]
Modified height of the box\[ = {\text{ }}28{\text{ }}cm - 1{\text{ }}cm = 27{\text{ }}cm.\]
Capacity / volume of the box:
\[
   = length \times width \times height \\
   = 44 \times 31 \times 27 \\
   = 36828c{m^3} \\
\]

Note: In this type of questions the S.I units must be kept in mind and always remove the given thickness from corresponding sides to calculate the capacity or volume of the box.