The number of ways of wearing 6 different rings on 5 fingers is:
$
(a)\,\,{5^6} \\
(b)\,\,{6^5} \\
(c)\,\,{5^5} \\
(d)\,\,{6^6} \\
$
Answer
588k+ views
Hint: To find the solution of this problem we use the concept of permutations. As it's given that any ring can be worn on any finger, so using this concept we first find a number of ways for one ring to be worn and then using it we can find the total number of ways.
Complete step-by-step answer:
Permutations and combinations, the various ways in which objects from a set may be selected, generally without replacement, to form subsets. This selection of subsets is called a permutation when the order of selection is a factor, a combination when order is not a factor.
Number of different rings = $ 6 $
Numbers of fingers = $ 5 $
As, there are $ 6 $ different rings that are to be worn in $ 5 $ fingers and there is no condition given in the question.
Therefore, for every ring there are $ 5 $ different ways available to put a ring in any finger.
So, for $ 6 $ different rings total number of available will be given as: $ {6^5} $
So, the correct answer is “Option B”.
Note: As, there is no condition given in the problem that how many rings can be worn in any finger, so one can put all rings in one finger or two, three or so. Hence, for each ring there are total five ways available as there are total five fingers given and hence for all six rings we can say total ways are equal to $ {6^5} $
Complete step-by-step answer:
Permutations and combinations, the various ways in which objects from a set may be selected, generally without replacement, to form subsets. This selection of subsets is called a permutation when the order of selection is a factor, a combination when order is not a factor.
Number of different rings = $ 6 $
Numbers of fingers = $ 5 $
As, there are $ 6 $ different rings that are to be worn in $ 5 $ fingers and there is no condition given in the question.
Therefore, for every ring there are $ 5 $ different ways available to put a ring in any finger.
So, for $ 6 $ different rings total number of available will be given as: $ {6^5} $
So, the correct answer is “Option B”.
Note: As, there is no condition given in the problem that how many rings can be worn in any finger, so one can put all rings in one finger or two, three or so. Hence, for each ring there are total five ways available as there are total five fingers given and hence for all six rings we can say total ways are equal to $ {6^5} $
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the name of Japan Parliament?

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

