The number of water molecules present in a drop of water (volume=$0.0018ml$) at room temperature is:
A.$6.023 \times {10^{19}}$
B.$1.084 \times {10^{18}}$
C.$4.84 \times {10^{17}}$
D.$6.023 \times {10^{23}}$
Answer
637.2k+ views
Hint: In this question, we have to calculate the number of entities in a volume of water. Simply use the unitary method to find the answer to this question. \[6.022 \times {10^{23}}\] is Avogadro's number and represents the number of atoms/molecules present in one mole of the substance. We shall use the mole concept to find the number of moles present and hence, the number of molecules.
Formula used: \[{\text{Density = }}\dfrac{{{\text{mass}}}}{{{\text{volume}}}}\]and ${\text{No}}{\text{. of moles = }}\dfrac{{{\text{Given mass}}}}{{{\text{Molar mass}}}}$
Complete step by step answer:
Rearranging the formulas of density, we have:
\[ \Rightarrow {\text{mass = density} \times \text{volume}}\]
Now the density of water =\[1{\text{g/ml}}\]. In the question we have the volume of water =\[0.0018{\text{mL}}\].
Hence, mass of \[0.0018{\text{mL}}\] water =\[1 \times 0.0018 = 0.0018{\text{gm}}\]. Molar mass of water =\[18{\text{gm/mol}}\].
Number of moles in \[0.0018{\text{gm}}\] of water can be calculated using formula for no. of moles = $\dfrac{{0.0018}}{{18}}$ \[ = 0.0001\;{\text{mole}}\].
The number of molecules of water in 1 mole = \[6.022 \times {10^{23}}\;{\text{molecules}}\].
Thus number of molecules of water in \[0.0001\;{\text{mole}}\] = \[6.022 \times {10^3} \times 0.0001 = 6.023 \times {10^{19}}\]
Hence, the number of water molecules present in a drop of water (volume = \[0.0018{\text{mL}}\]) at room temperature are \[6.023 \times {10^{19}}\].
Hence, the correct answer is option A.
Note:
The concept that a mole of any substance contains the same number of particles was formed out of research which was conducted by Italian physicist Amedeo Avogadro. Avogadro constant can be defined as the number of molecules, atoms, or ions in one mole of a substance: $6.022 \times {10^{23}}$ per mol. It is derived from the number of atoms of the pure isotope $^{{\text{12}}}{\text{C}}$ in 12 grams of that substance and is the reciprocal of atomic mass in grams. The formulae for the mole concept can be summarized as:
${\text{Number}}{\text{ of moles = }}\dfrac{{{\text{Mass of the Substance in grams}}}}{{{\text{Molar mass of a Substance}}}} = \dfrac{{{\text{Number of Atoms or Molecules}}}}{{6.022 \times {{10}^{23}}}}$.
These formulae can be used to establish relationships between formula mass, the mole, and Avogadro’s number can be applied to compute various quantities that describe the composition of substances and compounds.
Formula used: \[{\text{Density = }}\dfrac{{{\text{mass}}}}{{{\text{volume}}}}\]and ${\text{No}}{\text{. of moles = }}\dfrac{{{\text{Given mass}}}}{{{\text{Molar mass}}}}$
Complete step by step answer:
Rearranging the formulas of density, we have:
\[ \Rightarrow {\text{mass = density} \times \text{volume}}\]
Now the density of water =\[1{\text{g/ml}}\]. In the question we have the volume of water =\[0.0018{\text{mL}}\].
Hence, mass of \[0.0018{\text{mL}}\] water =\[1 \times 0.0018 = 0.0018{\text{gm}}\]. Molar mass of water =\[18{\text{gm/mol}}\].
Number of moles in \[0.0018{\text{gm}}\] of water can be calculated using formula for no. of moles = $\dfrac{{0.0018}}{{18}}$ \[ = 0.0001\;{\text{mole}}\].
The number of molecules of water in 1 mole = \[6.022 \times {10^{23}}\;{\text{molecules}}\].
Thus number of molecules of water in \[0.0001\;{\text{mole}}\] = \[6.022 \times {10^3} \times 0.0001 = 6.023 \times {10^{19}}\]
Hence, the number of water molecules present in a drop of water (volume = \[0.0018{\text{mL}}\]) at room temperature are \[6.023 \times {10^{19}}\].
Hence, the correct answer is option A.
Note:
The concept that a mole of any substance contains the same number of particles was formed out of research which was conducted by Italian physicist Amedeo Avogadro. Avogadro constant can be defined as the number of molecules, atoms, or ions in one mole of a substance: $6.022 \times {10^{23}}$ per mol. It is derived from the number of atoms of the pure isotope $^{{\text{12}}}{\text{C}}$ in 12 grams of that substance and is the reciprocal of atomic mass in grams. The formulae for the mole concept can be summarized as:
${\text{Number}}{\text{ of moles = }}\dfrac{{{\text{Mass of the Substance in grams}}}}{{{\text{Molar mass of a Substance}}}} = \dfrac{{{\text{Number of Atoms or Molecules}}}}{{6.022 \times {{10}^{23}}}}$.
These formulae can be used to establish relationships between formula mass, the mole, and Avogadro’s number can be applied to compute various quantities that describe the composition of substances and compounds.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

