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The number of $\sigma $ and $\pi $ -bonds in $F{{e}_{2}}{{(CO)}_{9}}$ , respectively are:
A. 22 $\sigma $ and 15 $\pi $
B. 23 $\sigma $ and 15 $\pi $
C. 22 $\sigma $ and 16 $\pi $
D. 15 $\sigma $ and 8 $\pi $

Answer
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Hint: If p-orbitals are going to overlap axially then it leads to the formation of sigma ($\sigma $) bond and if p-orbitals are going to overlap sideways then it leads to the formation of the pi ($\pi $ ) bond. Sigma bond is stronger than pi bond.

Complete answer:
- In the question it is given to find the number of sigma bonds and number of pi bonds present in the given compound.
- The given compound is $F{{e}_{2}}{{(CO)}_{9}}$ .
- To know about how many sigma bonds and how many pi bonds present in the given compound we should know the structure of the given compound.
- The structure of the given compound is as follows.
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- All single bonds are sigma bonds only.
- In CO, there are three bonds. Out of those three one bond is sigma bond and the other two bonds are pi bonds.
- All Fe-CO bonds are sigma bonds in nature.
- If CO contains a double bond in the above structure then it contains one sigma bond and one pi bond in it.
- Therefore the number of sigma bonds present in the given compounds is 22 and the total number of pi bonds is 15.

So, the correct option is A.

Note:
Triple bonds are stronger than the double bond. Because in triple bonds there are two pi bonds and one pi bond while in a double bond there is one sigma bond and one pi bond. Therefore triple bonds are stronger than pi bonds.