The number of rectangles excluding squares from a rectangle of sizes 9\[ \times \]6 is
A. 391
B. 791
C. 842
D. 250
Answer
661.5k+ views
Hint: Number the lines from 1 to 10 and 1 to 7 to count the rectangles. Then count the total number of squares one by one. After that, we will count the number of total rectangles excluding the squares.
Complete step by step solution: If you are given a grid of size 9\[ \times \]6 then the number of rectangles means you have to first choose two horizontal lines and two vertical lines from all the line.
As we can see the total number of vertical and horizontal lines is 7 and 10 respectively.
To make a rectangle, we need any two lines among vertical lines and any two from the horizontal ones,
Now, total number of rectangle are,
\[ = {}^{{\text{10}}}{{\text{C}}_{\text{2}}}{ \times }{}^{\text{7}}{{\text{C}}_{\text{2}}}\]
On using the formula, \[{}^{\text{n}}{{\text{C}}_{\text{r}}}{\text{ = }}\dfrac{{{\text{n!}}}}{{{\text{(n - r)!r!}}}}\], we get,
\[ = \dfrac{{10!}}{{2!\left( {10 - 2} \right)!}} \times \dfrac{{7!}}{{2!(7 - 2)!}}\]
On further simplification we get,
= \[\dfrac{{10 \times 9 \times 8!}}{{2!8!}} \times \dfrac{{7 \times 6 \times 5!}}{{2!5!}}\]
\[ = 45 \times 21\]
\[ = 945\]
Now if we try to calculate the number of the squares,
We have 1 unit size boxes, with the number of (9\[ \times \]6) boxes.
We have 2 unit size boxes, with the number of (8\[ \times \]5) boxes.
We have 3 unit size boxes, with the number of (7\[ \times \]4) boxes.
We have 4 unit size boxes, with the number of (6\[ \times \]3) boxes.
We have 5 unit size boxes, with the number of (5\[ \times \]2) boxes.
We have 6 unit size boxes, with the number of (4\[ \times \]1) boxes.
So, total number of squares \[ = {\text{ }}(9 \times 6){\text{ }} + {\text{ }}(8 \times 5){\text{ }} + {\text{ }}(7 \times 4){\text{ }} + {\text{ }}(6 \times 3){\text{ }} + {\text{ }}(5 \times 2){\text{ }} + {\text{ }}(4 \times 1)\]\[ = 54 + 40 + 28 + 18 + 10 + 4\] \[ = 154\]
Now, the number of rectangles excluding squares, \[ = 945 - 154\] \[ = 791\].
Hence the correct option is (B).
Note: While counting the number of squares we get n – 1 types of unit boxes if we get m horizontal lines and n vertical lines and \[m{\text{ }} > {\text{ }}n.{\text{ }}If{\text{ }}n{\text{ }} > {\text{ }}m\] then we have m – 1 types of unit boxes.
Complete step by step solution: If you are given a grid of size 9\[ \times \]6 then the number of rectangles means you have to first choose two horizontal lines and two vertical lines from all the line.
As we can see the total number of vertical and horizontal lines is 7 and 10 respectively.
To make a rectangle, we need any two lines among vertical lines and any two from the horizontal ones,
Now, total number of rectangle are,
\[ = {}^{{\text{10}}}{{\text{C}}_{\text{2}}}{ \times }{}^{\text{7}}{{\text{C}}_{\text{2}}}\]
On using the formula, \[{}^{\text{n}}{{\text{C}}_{\text{r}}}{\text{ = }}\dfrac{{{\text{n!}}}}{{{\text{(n - r)!r!}}}}\], we get,
\[ = \dfrac{{10!}}{{2!\left( {10 - 2} \right)!}} \times \dfrac{{7!}}{{2!(7 - 2)!}}\]
On further simplification we get,
= \[\dfrac{{10 \times 9 \times 8!}}{{2!8!}} \times \dfrac{{7 \times 6 \times 5!}}{{2!5!}}\]
\[ = 45 \times 21\]
\[ = 945\]
Now if we try to calculate the number of the squares,
We have 1 unit size boxes, with the number of (9\[ \times \]6) boxes.
We have 2 unit size boxes, with the number of (8\[ \times \]5) boxes.
We have 3 unit size boxes, with the number of (7\[ \times \]4) boxes.
We have 4 unit size boxes, with the number of (6\[ \times \]3) boxes.
We have 5 unit size boxes, with the number of (5\[ \times \]2) boxes.
We have 6 unit size boxes, with the number of (4\[ \times \]1) boxes.
So, total number of squares \[ = {\text{ }}(9 \times 6){\text{ }} + {\text{ }}(8 \times 5){\text{ }} + {\text{ }}(7 \times 4){\text{ }} + {\text{ }}(6 \times 3){\text{ }} + {\text{ }}(5 \times 2){\text{ }} + {\text{ }}(4 \times 1)\]\[ = 54 + 40 + 28 + 18 + 10 + 4\] \[ = 154\]
Now, the number of rectangles excluding squares, \[ = 945 - 154\] \[ = 791\].
Hence the correct option is (B).
Note: While counting the number of squares we get n – 1 types of unit boxes if we get m horizontal lines and n vertical lines and \[m{\text{ }} > {\text{ }}n.{\text{ }}If{\text{ }}n{\text{ }} > {\text{ }}m\] then we have m – 1 types of unit boxes.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

