Question

The number of ions formed on dissolving one molecule of $FeS{O_4}{(N{H_4})_2}S{O_4}.6{H_2}O$ is/are:
A.6
B.3
C.5
D.4

Answer 1

Hint:In this question we will be seeing a concept called double salt. We will also learn about how to split the given equation to find out the ions on dissolving the salt. We will learn to split or dissolve a particular salt on the basis of its properties.

Complete answer:
As we know before,
The compound that is given to us is a Double Salt.
Let’s split it to find the ions:
$FeS{O_4}.{(N{H_4})_2}.6{H_2}O \to F{e^{2 + }} + 2S{O_4}^{2 - } + 2N{H_4}^ + + 6{H_2}O$
So, based on the above split equation we get to know that after dissolving in water the ions of a given molecule is 5.

So, the correct answer to the above problem is option C.

Note:
Double salt is the combination of two different simple translucent salts. By different here, we imply that each salt in the blend has its own interesting gem structure. The property of a double salt is accordingly transformed from the properties of each salt in the blend. As a rule, the properties of the double salt framed won't be equivalent to the properties of its part single salts.
The quantity of particles in a compound relies upon the structure of the compound and the oxidation conditions of the components inside the compound. A component's oxidation state is the quantity of electrons that an iota has or needs comparative with the quantity of protons in its core. This decides the ionic charge of that particle, which is fundamental to depicting the ionic mixes it structures with different ions.