
The number of five digited numbers greater than 50,000 can be formed by using digits 0,1,1,5,9 is
A) 48
B) 24
C) 150
D) 30
Answer
508.5k+ views
Hint:
Here the digits given are 5 and we have to make numbers greater than 50000. So only two numbers can take place of ten thousandth value .those are 5 and 9 because others can make the number of 5 digits but not greater than 50000. So place them and use permutations or combinations.
Complete step by step solution:
Here they have given that the number should be five digited and is greater than 50,000.
So let’s sort the conditions.
1) The digit at ten-thousandth place can only be either 5 or 9.
2) So only four digits can form the remaining combination.
3) Also, note that 1 is the repeated digit.
4) The number of combinations formed by digit 5 will be equal to that of Number of combinations formed by digit 9.
So, combinations formed by digit 5 \[ = \dfrac{{4!}}{{2!}}\]
\[
\Rightarrow \dfrac{{24}}{2} \\
\Rightarrow 12 \\
\]
So, combinations formed by digit 9 will also be 12.
The total number of combinations is 24.
So option B is correct.
Note: 1)
The number formed is 5 digit number.
2) Digits 1 and 0 are not considered because they are already less than 5 and we are bind to form a 5 digit number.
3) 5 and 9 form the same number of combinations because the remaining numbers are the same.
Additional Information:
1) The combination is used when we need to do selection especially.
2) Like from similar things or dissimilar things, we have to select in different ways, patterns.
3) It is used in conditions of picking balls, picking a card, selecting a committee, forming a team, forming number.
Here the digits given are 5 and we have to make numbers greater than 50000. So only two numbers can take place of ten thousandth value .those are 5 and 9 because others can make the number of 5 digits but not greater than 50000. So place them and use permutations or combinations.
Complete step by step solution:
Here they have given that the number should be five digited and is greater than 50,000.
So let’s sort the conditions.
1) The digit at ten-thousandth place can only be either 5 or 9.
2) So only four digits can form the remaining combination.
3) Also, note that 1 is the repeated digit.
4) The number of combinations formed by digit 5 will be equal to that of Number of combinations formed by digit 9.
So, combinations formed by digit 5 \[ = \dfrac{{4!}}{{2!}}\]
\[
\Rightarrow \dfrac{{24}}{2} \\
\Rightarrow 12 \\
\]
So, combinations formed by digit 9 will also be 12.
The total number of combinations is 24.
So option B is correct.
Note: 1)
The number formed is 5 digit number.
2) Digits 1 and 0 are not considered because they are already less than 5 and we are bind to form a 5 digit number.
3) 5 and 9 form the same number of combinations because the remaining numbers are the same.
Additional Information:
1) The combination is used when we need to do selection especially.
2) Like from similar things or dissimilar things, we have to select in different ways, patterns.
3) It is used in conditions of picking balls, picking a card, selecting a committee, forming a team, forming number.
Recently Updated Pages
Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain why it is said like that Mock drill is use class 11 social science CBSE

Which of the following blood vessels in the circulatory class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Which of the following is nitrogenfixing algae a Nostoc class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells
