Question

The normality of $0.124M$${H_2}S{O_4}$ solution is

Answer 1

Hint: Normality is one of the methods of expressing the concentration of the solution. Normality of a given solution is best described as “the number of grams equivalent of the solute dissolved in one litre of solution”.

Complete answer:
As we know the molarity of solution of sulphuric acid from the given numerical, we use the formula that relates the molarity of solution with normality.
We know that ${H_2}S{O_4}$ is an acid so we determine its normality based on its basicity.
Basicity of sulphuric depends upon its tendency to replace hydrogen ions from its core structure. Since, sulphuric acid can replace both of its hydrogen ion, its basicity become $2$
General Formula of normality is $N = \dfrac{{Eq}}{V}$
Where $N$ is normality of solution
$Eq$ is number of gram equivalent of solute in the solution
$V$ is the total volume of solution in litres.
In terms of molarity and basicity, normality of solution is expressed as $N = M \times b$
Where $M$ is molarity of solution
$b$ Is basicity of acid
Now, put the value of basicity of acid and its molarity in the formula as mentioned in question we get,
$N = 0.124 \times 2$
After solving the above equation, we get,
$N = 0.248N$
Hence, The normality of the $O.124M$${H_2}S{O_4}$ solution is $0.248N$.

Note:
Normality is the temperature dependent property of a solution which varies with variation in temperature.
For bases, the product of molarity and acidity of base gives the value of normality of solution.
Do not get confused with the term formality which describes the number of formula mass dissolved in one litre of solution.