Question

The name of the compound ${\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{Zn}}{{\rm{O}}_{\rm{2}}}$ is:
A.sodium zinc oxide
B.sodium zincite
C.sodium zincate
D.zincite

Answer 1

Hint: We know that every compound has its name. There are two types of naming, general name and the IUPAC name. There are a set of guidelines to determine naming of a compound in IUPAC naming.

Complete step by step answer:

The given compound is ${\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{Zn}}{{\rm{O}}_{\rm{2}}}$ and we have to identify the correct name of it.

Let’s discuss all the options one by one.

Option A says the chemical name is sodium zinc oxide. But the correct formula for sodium zinc oxide is ${\rm{N}}{{\rm{a}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}{\rm{Zn}}$. So, option A is incorrect.

Option B says the chemical name of the compound is sodium zincite. But, the compound whose name is sodium zincite possess molecular formula of ${{\rm{H}}_{\rm{4}}}{\rm{N}}{{\rm{a}}_{\rm{2}}}{{\rm{O}}_{\rm{4}}}{\rm{Zn}}$. So, option B is not correct.

Option C says the chemical name of the compound is sodium zincate. Sodium zincate has molecular formula ${\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{Zn}}{{\rm{O}}_{\rm{2}}}$.

Option D says the chemical name of the compound is zincite. But the chemical formula of zincite is ZnO. So, option D is not correct.

Therefore, name of the compound ${\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{Zn}}{{\rm{O}}_{\rm{2}}}$
is sodium zincate.

Hence, the correct answer is option C.

Additional Information:

In aqueous solution of sodium zincate they release ions which conduct electricity. Therefore, they are termed as good conductors of electricity.

Note:
Zinc oxide is an amphoteric oxide that means it can react with both acids and bases to produce water and salt. Sodium zincate is produced by reaction of zinc oxide with sodium hydroxide. The reaction can be shown as below:

${\rm{ZnO}} + 2{\rm{NaOH}} \to {\rm{N}}{{\rm{a}}_2}{\rm{Zn}}{{\rm{O}}_2} + {{\rm{H}}_{\rm{2}}}{\rm{O}}$

In the sodium zincate salt, the zinc metal is present as part of negative ion (zincate ion), that is, ${\rm{Zn}}{{\rm{O}}_{\rm{2}}}^ - $.

${\rm{NaCl}} + {\rm{AgN}}{{\rm{O}}_{\rm{3}}} \to {\rm{AgCl(white ppt}}{\rm{.)}} + {\rm{NaN}}{{\rm{O}}_3}$

${\rm{NaBr}} + {\rm{AgN}}{{\rm{O}}_{\rm{3}}} \to {\rm{AgBr(pale yellow ppt}}{\rm{.)}} + {\rm{NaN}}{{\rm{O}}_3}$

${\rm{NaI}} + {\rm{AgN}}{{\rm{O}}_{\rm{3}}} \to {\rm{AgI(yellow ppt}}{\rm{.)}} + {\rm{NaN}}{{\rm{O}}_3}$