The moment of inertia of a square plate about a diagonal is $I_{d}$ and that about aside in its plane is $I_{s}$ then
A) $I_{s} = I_{d}$
B) $I_{s} < I_{d}$
C) $I_{s} > I_{d}$
D) None of these

Answer

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Hint: Inertia is the property of an object to resist the change in its position. Also, the moment of inertia is the measure of the resistance of a body to angular acceleration.

Complete step by step solution:
Step I:
The moment of inertia depends on the mass and angular velocity of the object. In the case of any rotating object, the moment of inertia is calculated by taking the square of the distance of each particle from the axis of rotation

^{'} {r^{2}}^{'}

and its mass

^{'} m^{'}

.
It is written as

I = m r^{2}

Step II:
The moment of inertia is higher for a body if more mass is distributed away from the rotational axis. For a square rotating about a diagonal equal mass is distributed about its rotational axis, thus its moment of inertia will be lower.
Step III:
In the case of a square plate, the moment of inertia is more about the side in its plane

I_{s}

as more mass will be distributed along the sides away from the plane of rotation. So its moment of inertia will also be higher.
But in the case of its diagonal, a square is a sum of two triangles. The moment of inertia is dependent on its mass and not on the axis of rotation, so its moment of inertia will be lower.

I_{s} > I_{d}

Therefore, option (C) is the correct answer.

Note:
The moment of inertia helps in calculating the force required to move an object. A higher moment of inertia means that a large amount of force is required to rotate the object, whereas small inertia describes that the force applied to rotate the object is smaller.