
The moment of force \[\overrightarrow{F}=2\widehat{i}+3\widehat{j}\] at the point (2,2) about the origin is given by?
A) \[2\widehat{k}\]
B) \[-2\widehat{k}\]
C) \[\widehat{k}\]
D) None of the above
Answer
559.2k+ views
Hint: Moment of force is also called torque. Torque is defined as the force which acts on a body and then the body starts rotating around some axis. So, the torque makes the body rotate. Torque is a vector quantity and it has both the magnitude and the direction.
Complete step by step solution:
We are given the force as \[\overrightarrow{F}=2\widehat{i}+3\widehat{j}\] and it is acting at the point (2,2). We need to find the torque about the origin. So the perpendicular distance is between the points P(2,2) and Q(0,0)
We know from the vector algebra position vector from the origin can be directly written as , \[\overrightarrow{r}=2\widehat{i}+2\widehat{j}\]
torque is given as \[\overrightarrow{\tau }=\overrightarrow{r}\times \overrightarrow{F}\]
\[\begin{align}
& \Rightarrow (2\widehat{i}+2\widehat{j})\times (2\widehat{i}+3\widehat{j}) \\
& =\left( \begin{matrix}
\widehat{i} & \widehat{j} & \widehat{k} \\
2 & 2 & 0 \\
2 & 3 & 0 \\
\end{matrix} \right) \\
& =0\widehat{i}+0\widehat{j}+2\widehat{k} \\
& \Rightarrow 2\widehat{k} \\
\end{align}\]
So, the correct answer is “Option A”.
Additional Information:
First of all, let us define what is a moment of force. The moment of force is a measure of the ability of the force acting on a particular body to rotate it around a given axis.
Note:
While calculating the torque we have to keep in our mind that it is a vector quantity and is given by the cross product of force acting on the body and the perpendicular distance from the axis of rotation. So, we have to consider the angle between the two vectors. But here we had calculated the cross product by using vector algebra, and the result is also a vector, so we do not need the angle between the two vectors.
Complete step by step solution:
We are given the force as \[\overrightarrow{F}=2\widehat{i}+3\widehat{j}\] and it is acting at the point (2,2). We need to find the torque about the origin. So the perpendicular distance is between the points P(2,2) and Q(0,0)
We know from the vector algebra position vector from the origin can be directly written as , \[\overrightarrow{r}=2\widehat{i}+2\widehat{j}\]
torque is given as \[\overrightarrow{\tau }=\overrightarrow{r}\times \overrightarrow{F}\]
\[\begin{align}
& \Rightarrow (2\widehat{i}+2\widehat{j})\times (2\widehat{i}+3\widehat{j}) \\
& =\left( \begin{matrix}
\widehat{i} & \widehat{j} & \widehat{k} \\
2 & 2 & 0 \\
2 & 3 & 0 \\
\end{matrix} \right) \\
& =0\widehat{i}+0\widehat{j}+2\widehat{k} \\
& \Rightarrow 2\widehat{k} \\
\end{align}\]
So, the correct answer is “Option A”.
Additional Information:
First of all, let us define what is a moment of force. The moment of force is a measure of the ability of the force acting on a particular body to rotate it around a given axis.
Note:
While calculating the torque we have to keep in our mind that it is a vector quantity and is given by the cross product of force acting on the body and the perpendicular distance from the axis of rotation. So, we have to consider the angle between the two vectors. But here we had calculated the cross product by using vector algebra, and the result is also a vector, so we do not need the angle between the two vectors.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

What are porins class 11 biology CBSE

Why is steel more elastic than rubber class 11 physics CBSE

Differentiate between red algae and brown algae class 11 biology CBSE

What is boron A Nonmetal B Metal C Metalloid D All class 11 chemistry CBSE

