
The molecule/molecules that has/have delocalised lone pair(s) of electron is/are:
A.A, B and C
B.A, C and D
C.A and B
D.Only B
Answer
564.3k+ views
Hint: They must be conjugation present for the lone pair to be delocalised. Only delocalised electrons show resonance. The double bond should be present adjacent to the lone pair bearing species.
Complete step by step solution:
Resonance is the displacement or shifting of a lone pair of electrons within the compound. One single resonating structure cannot explain all the properties of the compound so we make different structures by shifting the Pi electrons to define complete physical and chemical properties of the compound. The structures that are formed are known as resonating structure. Resonance helps in the stabilization of the compound. Resonance is a completely hypothetical concept and has no real significance.
There are various types of resonance:
Positive charge pi resonance:This happens when Pi bond is in conjugation with a positive charge and vacant orbital. The condition is that both of them must be present adjacent carbon.
Pi electron lone pair conjugation:Pi bonds in conjugation with lone pair and they are separated by just one sigma bond.
Pi bond free radical: When pi bond is in conjugation with free radical and they are separated by just one sigma bond.
Pi bond conjugation:When 2 Pi bonds are present on alternate positions to each other so that they can conjugate and show resonance.
Lone pair positive charge resonance: Lone pairs and positive charge are separated by just one sigma bond.
In the above molecules given the only molecule that show delocalisation is
As we can see that the double and lone pair is just separated by one sigma bond, hence resonance takes place.
Hence, the correct option is D.
Note:
Lone pairs are those species which do not involve resonance; they usually remain in hybrid orbitals. Delocalized lone pairs are those lone pairs which are in conjugation. They are present in unhybridized orbitals in order to show resonance.
Complete step by step solution:
Resonance is the displacement or shifting of a lone pair of electrons within the compound. One single resonating structure cannot explain all the properties of the compound so we make different structures by shifting the Pi electrons to define complete physical and chemical properties of the compound. The structures that are formed are known as resonating structure. Resonance helps in the stabilization of the compound. Resonance is a completely hypothetical concept and has no real significance.
There are various types of resonance:
Positive charge pi resonance:This happens when Pi bond is in conjugation with a positive charge and vacant orbital. The condition is that both of them must be present adjacent carbon.
Pi electron lone pair conjugation:Pi bonds in conjugation with lone pair and they are separated by just one sigma bond.
Pi bond free radical: When pi bond is in conjugation with free radical and they are separated by just one sigma bond.
Pi bond conjugation:When 2 Pi bonds are present on alternate positions to each other so that they can conjugate and show resonance.
Lone pair positive charge resonance: Lone pairs and positive charge are separated by just one sigma bond.
In the above molecules given the only molecule that show delocalisation is
As we can see that the double and lone pair is just separated by one sigma bond, hence resonance takes place.
Hence, the correct option is D.
Note:
Lone pairs are those species which do not involve resonance; they usually remain in hybrid orbitals. Delocalized lone pairs are those lone pairs which are in conjugation. They are present in unhybridized orbitals in order to show resonance.
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