The molar mass of barium nitrate (\[Ba{(N{O_3})_2}\]) is $261.35g/mol$. What is the mass of \[5.30 \times {10^{22}}\] formula units of \[Ba{(N{O_3})_2}\]?
Answer
584.7k+ views
Hint: We need to know that the barium nitrate is an inorganic salt which is composed of barium and nitrate ions having chemical formula \[Ba{(N{O_3})_2}\], Most of the barium salts, is colorless, toxic, and water-soluble. It burns with a green flame and is an oxidizer. It is found in white crystals having an odorless smell. The crystals of barium nitrate are lustrous in nature.
Complete answer:
We will solve this question step by step: It is a fact that \[6.022 \times {10^{23}}\] formula units of barium nitrate have a mass of $261.35g/mol$. This is what we specify when we say molar mass. And thus the mass of \[5.30 \times {10^{22}}\] formula units of barium nitrate is the quotient multiplied by the molar mass:
The mass of \[5.30 \times {10^{22}}\] formula units of \[Ba{(N{O_3})_2}\]
\[ = \dfrac{{5.30 \times {{10}^{22}}}}{{6.022 \times {{10}^{23}}}}mol \times 261.35g/mol\]
On simplification we get,
$ = 230 \times {10^{ - 1}}g$
Avogadro's number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to \[6.022 \times {10^{23}}\]. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction. One mole of a substance is equal to \[6.022 \times {10^{23}}\] units of that substance (such as atoms, molecules, or ions).
Note:
We have to remember that barium nitrate enhances the combustibility of many compounds even if it is not combustible. We have to know that it cannot be boiled as it decomposes on high temperature. It is an oxidizing agent which helps others to get burned. We need to remember that it is widely used in paints, in making explosives and it is also used in making green signal lights.
Complete answer:
We will solve this question step by step: It is a fact that \[6.022 \times {10^{23}}\] formula units of barium nitrate have a mass of $261.35g/mol$. This is what we specify when we say molar mass. And thus the mass of \[5.30 \times {10^{22}}\] formula units of barium nitrate is the quotient multiplied by the molar mass:
The mass of \[5.30 \times {10^{22}}\] formula units of \[Ba{(N{O_3})_2}\]
\[ = \dfrac{{5.30 \times {{10}^{22}}}}{{6.022 \times {{10}^{23}}}}mol \times 261.35g/mol\]
On simplification we get,
$ = 230 \times {10^{ - 1}}g$
Avogadro's number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to \[6.022 \times {10^{23}}\]. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction. One mole of a substance is equal to \[6.022 \times {10^{23}}\] units of that substance (such as atoms, molecules, or ions).
Note:
We have to remember that barium nitrate enhances the combustibility of many compounds even if it is not combustible. We have to know that it cannot be boiled as it decomposes on high temperature. It is an oxidizing agent which helps others to get burned. We need to remember that it is widely used in paints, in making explosives and it is also used in making green signal lights.
Recently Updated Pages
Which will be the least stable resonating structure class 11 chemistry CBSE

How many 5 digit telephone numbers can be construc-class-11-maths-CBSE

How do you find the angle of the resultant vector class 11 physics CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is the need and importance of classification class 11 biology CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference between physical and chemical change class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

