
The modulus of elasticity is dimensionally equivalent to
A. Surface tension
B. Stress
C. Strain
D. None of these
Answer
516.8k+ views
Hint: The modulus of elasticity can be defined as a measure of a material's ability to regain its original dimensions after the removal of a load or force. The modulus is the slope of the straight line portion of stress versus strain graph up to the proportional limit.
Complete step-by-step answer:
We have studied that the dimension of mass is represented by $M$ , length is represented by L and time is represented by $T$. So we have to find the dimensional formula of the modulus of elasticity in terms of M,L and T. The modulus of elasticity is dimensionally equivalent to stress because the modulus of elasticity $ = \dfrac{{stress}}{{strain}}$ and the unit of stain is nothing as it is unitless quantity. We know that the unit of stress is \[Newton/mete{r^2}\] or Pascal. We have studied that the dimension of Newton is equivalent to $ML{T^{ - 2}}$ because Newton is unit of force , $F = ma$ where $F$ is force, $m$ is mass and $a$ is acceleration and dimension of meter is $L$. Dimension of modulus of elasticity $ = \dfrac{{ML{T^{ - 2}}}}{{{L^2}}} = M{L^{ - 1}}{T^{ - 2}}$. Hence option B is the correct answer to this problem because the modulus of elasticity is dimensionally equivalent to stress.
Note: We know that the ratio of tangential stress to the shearing strain in the range of elastic limit. Since strain it is a dimensionless quantity because it is the ratio of change in length to the initial length of object. So the calculation of dimension or unit of The modulus of elasticity becomes more easy as it will be equal to the dimension or unit of stress.
Complete step-by-step answer:
We have studied that the dimension of mass is represented by $M$ , length is represented by L and time is represented by $T$. So we have to find the dimensional formula of the modulus of elasticity in terms of M,L and T. The modulus of elasticity is dimensionally equivalent to stress because the modulus of elasticity $ = \dfrac{{stress}}{{strain}}$ and the unit of stain is nothing as it is unitless quantity. We know that the unit of stress is \[Newton/mete{r^2}\] or Pascal. We have studied that the dimension of Newton is equivalent to $ML{T^{ - 2}}$ because Newton is unit of force , $F = ma$ where $F$ is force, $m$ is mass and $a$ is acceleration and dimension of meter is $L$. Dimension of modulus of elasticity $ = \dfrac{{ML{T^{ - 2}}}}{{{L^2}}} = M{L^{ - 1}}{T^{ - 2}}$. Hence option B is the correct answer to this problem because the modulus of elasticity is dimensionally equivalent to stress.
Note: We know that the ratio of tangential stress to the shearing strain in the range of elastic limit. Since strain it is a dimensionless quantity because it is the ratio of change in length to the initial length of object. So the calculation of dimension or unit of The modulus of elasticity becomes more easy as it will be equal to the dimension or unit of stress.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

