Question

The melting point of ice is ____ Kelvin.

Answer 1

Hint: We can say that the measurement of hotness or coldness of an object is temperature. The three temperature scales as,
- Celsius$\left( {^{\text{o}}{\text{C}}} \right)$
- Kelvin$\left( {\text{K}} \right)$
- Fahrenheit$\left( {^{\text{o}}{\text{F}}} \right)$

Formula used: Celsius to kelvin conversion:
We can convert celsius to kelvin using the formula,
$K{ = ^o}C + 273.15$
Where,
${\text{K}}$ is the temperature (in Kelvin).
$^{\text{o}}{\text{C}}$ is the temperature (in Celsius).

Complete step by step answer: We can define the melting point of a solid is the temperature at which it changes state from solid to liquid at atmospheric pressure. The melting point of ice at 1 atmospheric pressure is very close to ${0^ \circ }C.$
We can define the temperature of the backward change from liquid to solid is called the freezing point or crystallization point. For several substances the melting point and freezing points are the same.
We must remember that melting point of ice (in Celsius) is ${0^ \circ }C.$
Let’s now calculate the melting point of ice (in Kelvin).
$
  K{ = ^o}C + 273.15 \\
    \\
 $
Now we substitute the melting point (in Celsius) of ice we get,
$
  K = {0^ \circ }C + 273.15 \\
    \\
 $
Adding the above values we get,
$K = 273.15\,K$
We have obtained the melting point of ice (in Kelvin) as $273\,K$.

Note: We must remember that the boiling point is another term apart from melting point, and freezing point. The temperature at which the pressure exerted by the surrounding upon a liquid material is the same as the pressure exerted by the vapour of the liquid is called a boiling point and the pressure is called vapour pressure. We know that the boiling point of water is ${100^ \circ }C$. Now we can convert the boiling point of water in Kelvin scale as,
$
  K{ = ^o}C + 273.15 \\
    \\
 $
Now, substitute the value of boiling point of water we get,
$
  K = {100^ \circ }C + 273.15 \\
    \\
 $
Adding the above values we get,
$
  K = 373.15\,K \\
    \\
 $
The boiling point of ice (in Kelvin) is $373\,K$.
Let us now calculate the melting point of ice (in Fahrenheit).
We convert Celsius to Fahrenheit using the formula,
\[
  ^{\text{o}}{\text{F = 1}}{\text{.8}}\left( {^{\text{o}}{\text{C}}} \right){\text{ + 32}} \\
    \\
 \]
Now we substitute the boiling point of ice (in Celsius) we get,
\[
  ^{\text{o}}{\text{F}} = 1.8\left( {{0^{\text{o}}}{\text{C}}} \right) + 32 \\
    \\
 \]
We can add the above values we get,
\[^{\text{o}}{\text{F}} = {32^{\text{o}}}{\text{F}}\]
In Fahrenheit, we have calculated the melting point of ice as ${32^ \circ }F$.