Questions & Answers

Question

Answers

Answer
Verified

To find the percentage the formula is: $\dfrac{\text{given}\;\text{amount}}{\text{total}\;\text{amount}}\times 100$

And to find the amount from a given percentage the formula is: $\dfrac{\text{amount}\;\text{in}\;\text{percentage}(a{\scriptstyle{}^{0}/{}_{0}})\times \text{total}\;\text{amount}\;\text{of}\;\text{that}\;\text{percentage}}{100}$

The total marked price of 2 articles together is 6000,

Sales tax on A is 8%

Sales tax on B is 10%

The total sales tax on selling both the articles = 552

then, we have to calculate the marked price of each article.

Therefore, we will assume the marked price as some variable.

Let the marked price of A= Rs x.

and the marked price of B = Rs. (6000 − x)

Sales tax on A = 8% of x

= Rs $\left( \dfrac{\dfrac{2}{{{8}}}}{\dfrac{{1}{0}{0}}{25}}\times x \right)=\dfrac{2x}{25}$

Sales tax on B = 10% of (6000- x )

$=\dfrac{6000-x}{100}\times 1{0}$

= Rs $\left( \dfrac{6000-x}{10} \right)$

Now

According to the question

$\dfrac{2x}{5}+\dfrac{6000-x}{10}=552$ ①

[The Sum of the sales tax = 552 (given)]

Solving $eq$ ⑩

$\Rightarrow \dfrac{8x+60000-10x}{100}=552$

$=60000-2x=55200$

$\Rightarrow 2x=4800$

$\Rightarrow x=2400$

Therefore the marked price of A = Rs 2400

and the marked price of B = Rs (6000-x)

= Rs (6000-2400 )

= Rs 3600