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**Hint:**Assume a marked price of A and according to solve the question by finding the percentage of sales tax collected. It is given in the question that the total sales tax is 552.

To find the percentage the formula is: $\dfrac{\text{given}\;\text{amount}}{\text{total}\;\text{amount}}\times 100$

And to find the amount from a given percentage the formula is: $\dfrac{\text{amount}\;\text{in}\;\text{percentage}(a{\scriptstyle{}^{0}/{}_{0}})\times \text{total}\;\text{amount}\;\text{of}\;\text{that}\;\text{percentage}}{100}$

**Complete step by step solution:**Given that,

The total marked price of 2 articles together is 6000,

Sales tax on A is 8%

Sales tax on B is 10%

The total sales tax on selling both the articles = 552

then, we have to calculate the marked price of each article.

Therefore, we will assume the marked price as some variable.

Let the marked price of A= Rs x.

and the marked price of B = Rs. (6000 − x)

Sales tax on A = 8% of x

= Rs $\left( \dfrac{\dfrac{2}{{{8}}}}{\dfrac{{1}{0}{0}}{25}}\times x \right)=\dfrac{2x}{25}$

Sales tax on B = 10% of (6000- x )

$=\dfrac{6000-x}{100}\times 1{0}$

= Rs $\left( \dfrac{6000-x}{10} \right)$

Now

According to the question

$\dfrac{2x}{5}+\dfrac{6000-x}{10}=552$ ①

[The Sum of the sales tax = 552 (given)]

Solving $eq$ ⑩

$\Rightarrow \dfrac{8x+60000-10x}{100}=552$

$=60000-2x=55200$

$\Rightarrow 2x=4800$

$\Rightarrow x=2400$

Therefore the marked price of A = Rs 2400

and the marked price of B = Rs (6000-x)

= Rs (6000-2400 )

= Rs 3600

**Note:**In this type of question do not assume 2 variables. With one variable we can solve this question. Here we were dealing with tax which is paid annually. It’s important to understand the rate of interest. If we are dealing with interest then it can be monthly also. So, while solving such a question please keep our eyes on this.

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